How far apart are two point charges....

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SUMMARY

The discussion centers on calculating the distance between two point charges of 75.0 nC that exert a force of 1.00 N on each other using Coulomb's Law, represented by the equation F = k Q1Q2/r². Participants clarify the correct values for constants, specifically the electrostatic constant k, which is approximately 9.0 x 10⁹ N m²/C², and the conversion of nanocoulombs to coulombs. The calculation reveals that the distance r is derived from the equation r = √(k Q1Q2/F), leading to a value that indicates a misunderstanding of the physical implications of the calculated distance.

PREREQUISITES
  • Coulomb's Law and its application in electrostatics
  • Understanding of charge units, specifically nanocoulombs (nC) and coulombs (C)
  • Basic algebra and square root calculations
  • Knowledge of the electrostatic constant (k) and its significance
NEXT STEPS
  • Study the derivation and application of Coulomb's Law in electrostatics
  • Learn about the conversion between nanocoulombs and coulombs
  • Explore the implications of distance calculations in electrostatic force scenarios
  • Investigate the concept of electric field strength and its relation to point charges
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Students in physics, educators teaching electrostatics, and anyone interested in understanding the principles of electric forces and charge interactions.

snowjoe
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1. How far apart must two point charges of 75.0 nC be to have a force of 1.00 N between them?

Homework Equations

F = k Q1Q2/r2[/B]3. 1N = 9e10 * 75e-10 squared/r squared
r2= 9e10 * 75e-10 squared/1N
r2= 9*75*75e-10
r2= 5.0625e-7
r= square root of 5.0625 * square root of e-7

if this is right so far then i just have an
algebra issue, what is the square root of e-7? can it be e-3.5?, if so, what is the value of e-3.5?

 
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e-7 means 1x10^(-7) so you are right sqrt(e-7)= e-3,5
 
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snowjoe said:
1. How far apart must two point charges of 75.0 nC be to have a force of 1.00 N between them?

Homework Equations

F = k Q1Q2/r2[/B]3. 1N = 9e10 * 75e-10 squared/r squared
r2= 9e10 * 75e-10 squared/1N
r2= 9*75*75e-10
r2= 5.0625e-7
r= square root of 5.0625 * square root of e-7

if this is right so far then i just have an
algebra issue, what is the square root of e-7? can it be e-3.5?, if so, what is the value of e-3.5?
You also need to include the units for r .
 
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snowjoe said:
3. 1N = 9e10 * 75e-10 squared/r squared
Better check your value of k. And Q.
nano = 10-9, not 10-10.
 
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rude man, isn't an nC a C/e9? which gives nC as 1.6 * e (19-9) 10? value of k i am using 9 as approximation, good enough, k= 9.0 e9
 
snowjoe said:
rude man, isn't an nC a C/e9? which gives nC as 1.6 * e (19-9) 10? value of k i am using 9 as approximation, good enough, k= 9.0 e9
Where does 1.6 come from?
 
a Coulomb i take is 1.6 X e19 units of charge
 
i grow confuseder, this radius is in meters, no? yet i'mgetting values that are out of the realm of possibility. square the point charges, which are nC, which is on the order of e10, so squared, e20. multiply this by k, which is on the order of e9, getting e29, so the square root of this is the r? That still gives e14.5, in meters, pretty sure no force exists between these charges at several trillion meters. obviously I've gone awry, where?
 
snowjoe said:
i grow confuseder, this radius is in meters, no? yet i'mgetting values that are out of the realm of possibility. square the point charges, which are nC, which is on the order of e10,
1 nC = 10-9 C. C (coulomb) is the unit of charge, you mix it with the elementary charge, which is 1.6 `10-19 C.
 
  • #10
snowjoe said:
a Coulomb i take is 1.6 X e19 units of charge
A single electron has a charge of -1.6×10-19 Coulombs .

A single proton has a charge of 1.6×10-19 Coulombs .

These values have nothing to do with your stated problem.
 
  • #11
then my problem is the relationship between electrons/protons and Coulombs. How would one calculate the number of e/p in a fraction of a Coulomb, such as one billionth, a nC?
 
  • #12
snowjoe said:
then my problem is the relationship between electrons/protons and Coulombs. How would one calculate the number of e/p in a fraction of a Coulomb, such as one billionth, a nC?
N protons have a total charge of N×(1.6×10-19)C .

So solve
N×(1.6×10-19)C = one billionth, a nC​
 
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  • #13
SammyS said:
N protons have a total charge of N×(1.6×10-19)C .

So solve
N×(1.6×10-19)C = one billionth, a nC​
thank you.
 
  • #14
SammyS said:
N protons have a total charge of N×(1.6×10-19)C .

So solve
N×(1.6×10-19)C = one billionth, a nC​
so, a billionth of a Coulomb is 1.6e-10, and a billionth of the particles in a Coulomb is 6.25e-9?
 
  • #15
SammyS said:
N protons have a total charge of N×(1.6×10-19)C .

So solve
N×(1.6×10-19)C = one billionth, a nC​
N(1.6e-19)=e-9
N=e-9C/1.6e-19C = 6.25e9 = nC ??

then what is the flaw in calculating a nC by dividing C by n, as 1.6e19/e9 = 1.6e10
 
  • #16
snowjoe said:
N(1.6e-19)=e-9
N=e-9C/1.6e-19C = 6.25e9 = nC ??

then what is the flaw in calculating a nC by dividing C by n, as 1.6e19/e9 = 1.6e10
The question asks force between two point charges.

There is NO mention of how many electrons or how many protons are involved.

Use Coulomb's Law.
 
  • #17
Thanks, SS, But I'm asking about the math, where did i go wrong in calculating a nC by dividing 1.6e19 by e9?
 
  • #18
snowjoe said:
Thanks, SS, But I'm asking about the math, where did i go wrong in calculating a nC by dividing 1.6e19 by e9?
Forget the 1.6×10-19, 1.6×1019, etc. The charge of an electron has nothing to do with this.

nano is a prefix for metric units. nano means 10-9.

1 Coulomb is the basic unit of charge in the SI system of units. It is NOT the charge of an electron or proton.

1 nano-Coulomb is 1×109 Coulombs.
 
  • #19
is it not true that in a Coulomb there are 1.6 e19 units of charge, this unit of charge being the charge carried by one electron or proton?
 
  • #20
snowjoe said:
is it not true that in a Coulomb there are 1.6 e19 units of charge, this unit of charge being the charge carried by one electron or proton?
Yes that's true, but that fact is not needed anywhere in using Coulomb's Law.
 

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