- #1

snowjoe

- 16

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**1. How far apart must two point charges of 75.0 nC be to have a force of 1.00 N between them?**

## Homework Equations

F = k Q1Q2/r2[/B]**3. 1N = 9e10 * 75e-10 squared/r squared**

r2=

r2=

**9e10 * 75e-10 squared/1N**

r2= 9*75*75e-10

r2= 5.0625e-7

r= square root of 5.0625 * square root of e-7

if this is right so far then i just have analgebra issue, what is the square root of e-7? can it be e-3.5?, if so, what is the value of e-3.5?r2= 9*75*75e-10

r2= 5.0625e-7

r= square root of 5.0625 * square root of e-7

if this is right so far then i just have an