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1. Homework Statement

1. Homework Statement

A bullet is shot at an angle of 35

^{o}with a speed of 90 m/s. I assume that air resistance is ignored.

Calculate bullet's distance from launch site 2,5 seconds after the shot.

## Homework Equations

[/B]

x = v

_{ox}* t

v

_{ox}= v

_{o}* cosθ

## The Attempt at a Solution

[/B]

The horizontal speed should stay as it is.

v

_{o}= 90 m/s

t = 2,5 s

θ = 35

^{o}

x = v

_{ox}* t = v

_{o}* cosθ * t = 90 m/s * cos 35

^{o}* 2,5 s = 184,309... m ≈ 184 m

The book says that the answer should be 210 m. I cannot think of any other way to solve this.