Calculating Force and Impulse of a Bullet Hitting a Man

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SUMMARY

The discussion focuses on calculating the momentum and average force exerted by a bullet upon impact with a man. A bullet with a mass of 0.011 kg, traveling at 850 m/s, has a momentum of 9.35 N/s before impact. The average force exerted on the man, calculated using the impulse-momentum theorem, is -93.5 N, indicating a direction opposite to the bullet's motion. The negative sign in force arises from the convention of direction in impulse calculations, which can lead to confusion regarding the nature of the force.

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  • Understanding of momentum (p = mv)
  • Familiarity with impulse (I = Pf - Pi)
  • Knowledge of force calculations (F = I/t)
  • Basic physics concepts regarding directionality of forces
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  • Explore real-world applications of momentum in collision scenarios
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StormPix
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Homework Statement


A bullet of mass 0.011 kg is fired at a speed of 850 m/s. It embeds itself in a man of mass 90 kg.

a) Find the momentum of the bullet before it strikes the man.

b) Assuming it takes 0.1 seconds for the bullet to come to rest after hitting the man, calculate the average force that the bullet exerts on the man.

Homework Equations


p=mv
I=Pf - Pi
F=I/t

The Attempt at a Solution


a) Po = m*Vo = (0.011 kg)(850 m/s) = 9.35 N/s

b) I = Pf - Po = (0.011 kg)(0 m/s) - 9.35 N/s = - 9.35 N/s
F = I/t = -9.35 N/s / 0.1 s = -93.5 N

Question is why is the force negative. Shouldn't it be positive as the force is directed in the same direction as the bullet's movement and thus a positive direction?
 
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StormPix said:
Question is why is the force negative. Shouldn't it be positive as the force is directed in the same direction as the bullet's movement and thus a positive direction?
Yes, the force on the man should be positive. But did you calculate the impulse of the force on the man or did you calculate the impulse of the force on the bullet?
 

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