- #1

hamza2095

- 28

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## Homework Statement

A bullet with a mass of 0.045 kg is shot at 560m/s fwd, and it gets dislodged in a stationary block that is 0.5kg.

The collision lasts 0.35 seconds. What is the force imparted by the bullet on the block?

## Homework Equations

F=(m(vf-vi))/t

## The Attempt at a Solution

F=(0.045kg(0-560m/s))/0.35s

F=-72N [FWD]

It doesn't make sense that the force the bullet has on the block is backwards 72N[BWD], so I'm guessing that's the force of the block on the bullet, therefore using Newton's 3rd law which if F Action= -F reaction i get the force of the bullet on the block is 72N [FWD]

Is this right, shouldn't the initial calculation be the final answer for the question? Help is appreciated