How Far Did Big Bertha's Shell Travel?

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SUMMARY

The discussion focuses on calculating the distance traveled and the time of flight for a shell fired from the Big Bertha gun during World War 1. The initial speed of the shell is 2.26 km/s, and it is launched at an angle of 65.8 degrees. The acceleration due to gravity is 9.8 m/s². Participants are struggling with the calculations, particularly in converting units and applying the correct kinematic equations.

PREREQUISITES
  • Understanding of kinematic equations in physics
  • Knowledge of projectile motion concepts
  • Ability to convert units between kilometers and meters
  • Familiarity with basic algebra for solving equations
NEXT STEPS
  • Learn how to apply the kinematic equation for projectile motion
  • Study the conversion of units, specifically between kilometers and meters
  • Explore the derivation of time of flight for projectiles
  • Investigate the impact of launch angle on projectile distance
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Students studying physics, educators teaching projectile motion, and anyone interested in historical artillery calculations.

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Homework Statement


During World War 1, the Germans had a gun called Big Bertha that was used to shell Paris. The shell had an initial speed of 2.26 km/s at an initial inclination of 65.8 degrees to the horizontal. The acceleration of gravity is 9.8 m/s^2. How far away did the shell hit? Answer in units of km.
How long was it in the air? Answer in units of s.


Homework Equations


Vf= Vi + a (tf-ti)
y= yi + vit + 1/2 at^2.


The Attempt at a Solution


I did it several different ways and keep getting answers that are wrong. I got 4.10 s for time, then I got .420s and .840 s. I keep getting the wrong answer. Once I figure out how to do time, I'll be able to do the distance part. Keep in mind the a is in meters per second but kilometers is required in the answer.
 
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Which of the two eqns did you use to find the time of flight t? What values did substitute?
 

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