How far does a baseball player slide before coming to rest at third base?

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SUMMARY

A baseball player sliding into third base at an initial speed of 7.90 m/s experiences a coefficient of kinetic friction of 0.41 with the ground. To determine the distance the player slides before coming to rest, the net force equation f(net) = ma is applied, where the frictional force is calculated as f(friction) = μ(k) * g * m. The acceleration is derived as a = μ(k) * g, and the distance can be calculated using the kinematic equation d = 1/2 * a * t^2 + v(initial) * t, with the understanding that gravitational acceleration g is negative.

PREREQUISITES
  • Understanding of Newton's second law of motion (f(net) = ma)
  • Knowledge of kinetic friction and its coefficient (μ(k))
  • Familiarity with kinematic equations for uniformly accelerated motion
  • Basic principles of energy conservation in physics
NEXT STEPS
  • Calculate the acceleration using the formula a = μ(k) * g
  • Apply the kinematic equation d = 1/2 * a * t^2 + v(initial) * t to find the distance
  • Explore the concept of energy conservation in sliding motion
  • Review examples of similar physics problems involving friction and motion
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and motion, as well as educators seeking to explain concepts of friction and energy conservation in practical scenarios.

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Homework Statement


A baseball player slides into third base with an initial speed of 7.90 m/s. If the coefficient of kinetic friction between the player and the ground is .41, how far does the player slide before coming to rest?


Homework Equations





The Attempt at a Solution



I have absolutely no idea how to solve this question.
 
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I'll start it for you:

f(net) = ma

f(friction) = ma

mu(k)*g*m = ma

mu(k)*g = a

Then you can use these two formulas and you should be able to solve it:

a = (v(final)-v(initial))/t

d = 1/2*a*t^2 + v(initial)tJust a hint: remember that g is negative.
 
The energy the player expends sliding is frictional force times distance. The initial energy of the player coming in is (1/2)*m*v^2. Equate them.
 

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