How Far Does the Block Travel After Being Launched by a Compressed Spring?

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Homework Help Overview

The problem involves a block launched by a compressed spring on a frictionless surface, transitioning to an incline with kinetic friction. Participants are exploring how to calculate the distance the block travels after being launched, considering energy conservation and projectile motion principles.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss using work and energy methods to find the block's velocity at the top of the incline and how to incorporate friction into their calculations. Questions arise about the correct distance to use in work calculations and the direction of motion.

Discussion Status

Some participants have made progress in calculating the block's velocity and are seeking clarification on the next steps. Others are exploring different interpretations of the problem and how to apply the concepts of work and energy effectively.

Contextual Notes

There are variations in the problem parameters among participants, including different spring constants, compression distances, and coefficients of friction. This may affect the approaches discussed.

jfbueno
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The spring in the figure has a spring constant of 1100 N/m. It is compressed 16.0 cm, then launches a 200g block. The horizontal surface is frictionless, but the block's coefficient of kinetic friction on the incline is 0.180. What distance D does the block sail through the air?

heres a picture that should help.
 

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Well? Show your work and indicate where you got stuck.

Hint: Use a combination of energy methods and projectile motion kinematics.
 
Well, I first tried to use work and kinetic friction to find the horizontal distance of the hill however once I reached to the end of my calculations I figured that what I was doing found the the entire distance that the block travels. So then I tried using the conservation of energy to find the velocity of the block at the top of the hill but I don't know how to incorporate the coefficient of friction into that equation.
 
I figure that If i can find the velocity of the block at the top of the hill then the rest of the problem is cake with kinematics
 
jfbueno said:
So then I tried using the conservation of energy to find the velocity of the block at the top of the hill but I don't know how to incorporate the coefficient of friction into that equation.
Figure out the force of friction and then the work the friction does on the block as the block slides up the incline.
 
Would the distance I use for W=Fd in this equation be the horizontal or vertical distance. Because if its the vertical distance then i can solve for v but if its the horizontal then i have 2 variables in my equation.
 
jfbueno said:
Would the distance I use for W=Fd in this equation be the horizontal or vertical distance.
What direction does the block move?
Because if its the vertical distance then i can solve for v but if its the horizontal then i have 2 variables in my equation.
You're given the angle of the incline.
 
Ok, I found the velocity of the block at the top of the incline. Which kinematic equation and in which direction should i start?
 
From the moment the block shoots off the incline, it's a projectile motion problem. You have the initial speed and direction.
 
  • #10
I have the same problem on my physics homework, the only difference is that the spring constant is 1300, the spring is compressed 14cm and the coefficient kinetic friction is .22.

I found the velocity to be 11.225 m/s

I know W=FD = (F*uk)D = mgcos45*uk*h/cos45 =mgh*uk = .8624

I tried to read over the help given already but I really don't understand what to do, is there any further help anyone can give me??
 
  • #11
julz3216 said:
I have the same problem on my physics homework, the only difference is that the spring constant is 1300, the spring is compressed 14cm and the coefficient kinetic friction is .22.

I found the velocity to be 11.225 m/s

I know W=FD = (F*uk)D = mgcos45*uk*h/cos45 =mgh*uk = .8624

I tried to read over the help given already but I really don't understand what to do, is there any further help anyone can give me??
Now find the block's speed at the top of the ramp, as it shoots into the air. Then use that to determine the horizontal distance it flies before hitting the ground.
 

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