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Finding time of how long the block travels (SHM)

  1. Nov 20, 2016 #1
    1. The problem statement, all variables and given/known data
    A small block is attached to an ideal spring and is moving in SHM on a horizontal, frictionless surface. When the amplitude of the motion is 0.090 m , it takes the block 2.52 sto travel from x= 0.090 m to x= -0.090 m .

    If the amplitude is doubled, to 0.180 m , how long does it take the block to travel from x= 0.180 m to x= -0.180 m ?

    If the amplitude is doubled, to 0.180 m , how long does it take the block to travel from x= 0.090 m to x= -0.090 m ?


    2. Relevant equations
    x=Acos(ωt+Φ)

    3. The attempt at a solution

    I assume that you will be doing the same thing for the second question as you do for part 1.

    I tried to set up a ratio but I think i did it wrong:

    0.090m/0.252s = 0.180/t
    and got t = 0.504 s but that answer is wrong. I'm not sure what to do with the initial and final displacements.
     
  2. jcsd
  3. Nov 20, 2016 #2

    cnh1995

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    How are length and time period of the pendulum related? It is not a linear relation.
     
  4. Nov 20, 2016 #3
    I found an alternative way to solve this. Do I solve for the period by multiply time by 2 and then finding ω?
     
  5. Nov 20, 2016 #4

    cnh1995

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  6. Nov 20, 2016 #5

    cnh1995

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    Last edited: Nov 20, 2016
  7. Nov 20, 2016 #6
    Okay! Thank you!
     
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