Finding time of how long the block travels (SHM)

[Vanessa Avila]

Homework Statement

A small block is attached to an ideal spring and is moving in SHM on a horizontal, frictionless surface. When the amplitude of the motion is 0.090 m , it takes the block 2.52 sto travel from x= 0.090 m to x= -0.090 m .

If the amplitude is doubled, to 0.180 m , how long does it take the block to travel from x= 0.180 m to x= -0.180 m ?

If the amplitude is doubled, to 0.180 m , how long does it take the block to travel from x= 0.090 m to x= -0.090 m ?

Homework Equations

x=Acos(ωt+Φ)

The Attempt at a Solution

[/B]
I assume that you will be doing the same thing for the second question as you do for part 1.

I tried to set up a ratio but I think i did it wrong:

0.090m/0.252s = 0.180/t
and got t = 0.504 s but that answer is wrong. I'm not sure what to do with the initial and final displacements.

 

[cnh1995]

Homework Statement

A small block is attached to an ideal spring and is moving in SHM on a horizontal, frictionless surface. When the amplitude of the motion is 0.090 m , it takes the block 2.52 sto travel from x= 0.090 m to x= -0.090 m .

If the amplitude is doubled, to 0.180 m , how long does it take the block to travel from x= 0.180 m to x= -0.180 m ?

If the amplitude is doubled, to 0.180 m , how long does it take the block to travel from x= 0.090 m to x= -0.090 m ?

Homework Equations

x=Acos(ωt+Φ)

The Attempt at a Solution

[/B]
I assume that you will be doing the same thing for the second question as you do for part 1.

I tried to set up a ratio but I think i did it wrong:

0.090m/0.252s = 0.180/t
and got t = 0.504 s but that answer is wrong. I'm not sure what to do with the initial and final displacements.

How are length and time period of the pendulum related? It is not a linear relation.

 

[Vanessa Avila]

How are length and time period of the pendulum related? It is not a linear relation.

I found an alternative way to solve this. Do I solve for the period by multiply time by 2 and then finding ω?

 

[cnh1995]

I found an alternative way to solve this. Do I solve for the period by multiply time by 2 and then finding ω?

I am not sure about this method.
This will help.
https://www.google.co.in/url?sa=t&s...QILTAD&usg=AFQjCNFwkr2YvilUhhXYYipLP3QEVn6Mrg

 

[cnh1995]

I am not sure about this method.
This will help.
https://www.google.co.in/url?sa=t&source=web&rct=j&url=https://en.m.wikipedia.org/wiki/Pendulum#Period_of_oscillation&ved=0ahUKEwiq9IOM2rjQAhXGM48KHSiSDMoQygQILTAD&usg=AFQjCNFwkr2YvilUhhXYYipLP3QEVn6Mrg

Oh, sorry! I read the question wrong.
I think you will need the sinusoidal equation for that. Forget about the pendulum..!

 

[Vanessa Avila]

Oh, sorry! I read the question wrong.
I think you will need the sinusoidal equation for that. Forget about the pendulum..!

Okay! Thank you!