How Far Does the Student Swim Across the River?

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SUMMARY

The discussion centers on a physics problem involving a student swimming across a 40 m wide river while being carried 30 m downstream. The student's swimming speed in still water is 1.2 m/s. To determine the total distance the student swims, the problem requires calculating the hypotenuse of a right triangle formed by the river's width and the downstream distance. The solution involves using the Pythagorean theorem to find the resultant distance swum.

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1. In still water, a student can swim at 1.2 m/s. She swims perpendicularly across a 40 m wide river, landing 30 m downstream. In crossing the river, what distance does the student move?



2. d=df-di, cosine, sine, tangent



3. Again, i tried drawing out a picture. I made 40m the x axis, and 30m the y axis. Am i trying to solve for the hypoteneuse? Also, what am i suppossed to do with the 1.2m/s. is it just there to try and mess me up? or is it important for the question?
 
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Please don't type in bold face; it is difficult (for me) to read.

dance_sg said:
Am i trying to solve for the hypoteneuse?
That's what I would do.

dance_sg said:
Also, what am i suppossed to do with the 1.2m/s.
Data sufficiency.
 
sorry. i will remember that for next time.

and ok! thank you. i figured it out
 

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