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Catchingupquickly

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## Homework Statement

Sandra needs to deliver 20 cases of celery to the farmers' market directly east across the river, which is 32 meters wide. Her boat can move at 2.5 km/h in still water. The river has a current of 1.2 km/h flowing downstream, which happens to be moving in a southerly direction.

a) Where will Sandra end up if she aims her boat directly across the river?

b) How far will she have to walk to reach the market?

c) How could Sandra end up at her destination without walking?

d) Which route will result in the shortest time for Sandra to reach her destination? Sandra can walk at 0.72 m/s when she is pulling her wagon loaded with all 20 cases of celery. She has her wagon pre-loaded on the boat.

## Homework Equations

For a) ## tan\Theta = {\frac {opposite} {adjacent}}##b) nilc) ## sin\alpha = {\frac {opposite} {hypotenuse}}##d) ## tan\alpha = {\frac {opposite} {adjacent}}#### \Delta t = {\frac {\Delta d} {\vec v}}#### The Attempt at a Solution

[/B]

a)

## tan\Theta = {\frac {opposite} {adjacent}}

\\ = {\frac {1.2km} {2.5km}}

\\ \Theta = \tan^{-1} \left ( {\frac {1.2km} {2.5km}} \right)

\\ = 25.6##

26 degrees

Next, the distance.

##tan\Theta = {\frac {opposite} {adjacent}}

\\tan26 = {\frac {\vec d_2} {32m}}

\\ \vec d_2 = 15.6##

Sandra ends up 16 meters [East 26 degrees South] on the opposite shore.

b) She has to walk 16 meters north to get to the market

c) She needs to aim her boat to the Northeast.

##sin\alpha = {\frac {opposite} {hypotenuse}}

\\ \alpha = \sin^{-1} \left ( {\frac {1.2km} {2.5km}} \right)

\\ \alpha = 28.7##

She needs to aim East 29 degrees North

d) ##tan\alpha = {\frac {opposite} {adjacent}}

\\ adjacent = {\frac {opposite} {tan\alpha}}

\\ = {\frac {1.2km} {tan29}}

\\ = 2.16 km/h##

conversion to m/s

## {\frac {(2.16)(1000)} {3600}}

\\ = 0.6 m/s##Finally, comparison of sailing vs walking speeds

## \Delta t = {\frac {\Delta d} {\vec v}}

\\ = {\frac {32m} {0.6m/s}}

\\ = 53.3##

## {\frac {16m} {0.72m/s}}

\\ = 22.2##

It takes her 22 seconds to walk from 16m away versus the 53 seconds it would take her to sail directly there.

Am I correct in any of this?