Velocity Vectors and Navigation Across A River

• Catchingupquickly
In summary, Sandra needs to deliver 20 cases of celery to the farmers' market directly east across the river, which is 32 meters wide. Her boat can move at 2.5 km/h in still water. The river has a current of 1.2 km/h flowing downstream, which happens to be moving in a southerly direction.a) If Sandra aims her boat directly across the river, she will end up at the farmers' market 16 meters east of her starting point.b) Sandra will have to walk 16 meters north to reach the market.c) Sandra needs to aim her boat to the Northeast in order to reach her destination.d) Sandra can walk at 0
Catchingupquickly

Homework Statement

Sandra needs to deliver 20 cases of celery to the farmers' market directly east across the river, which is 32 meters wide. Her boat can move at 2.5 km/h in still water. The river has a current of 1.2 km/h flowing downstream, which happens to be moving in a southerly direction.

a) Where will Sandra end up if she aims her boat directly across the river?

b) How far will she have to walk to reach the market?

c) How could Sandra end up at her destination without walking?

d) Which route will result in the shortest time for Sandra to reach her destination? Sandra can walk at 0.72 m/s when she is pulling her wagon loaded with all 20 cases of celery. She has her wagon pre-loaded on the boat.

Homework Equations

For a) ## tan\Theta = {\frac {opposite} {adjacent}}##b) nilc) ## sin\alpha = {\frac {opposite} {hypotenuse}}##d) ## tan\alpha = {\frac {opposite} {adjacent}}#### \Delta t = {\frac {\Delta d} {\vec v}}##

The Attempt at a Solution

[/B]
a)

## tan\Theta = {\frac {opposite} {adjacent}}
\\ = {\frac {1.2km} {2.5km}}
\\ \Theta = \tan^{-1} \left ( {\frac {1.2km} {2.5km}} \right)
\\ = 25.6##

26 degrees

Next, the distance.

\\tan26 = {\frac {\vec d_2} {32m}}
\\ \vec d_2 = 15.6##

Sandra ends up 16 meters [East 26 degrees South] on the opposite shore.

b) She has to walk 16 meters north to get to the market

c) She needs to aim her boat to the Northeast.

##sin\alpha = {\frac {opposite} {hypotenuse}}
\\ \alpha = \sin^{-1} \left ( {\frac {1.2km} {2.5km}} \right)
\\ \alpha = 28.7##

She needs to aim East 29 degrees North

d) ##tan\alpha = {\frac {opposite} {adjacent}}
\\ adjacent = {\frac {opposite} {tan\alpha}}
\\ = {\frac {1.2km} {tan29}}
\\ = 2.16 km/h##

conversion to m/s

## {\frac {(2.16)(1000)} {3600}}
\\ = 0.6 m/s##Finally, comparison of sailing vs walking speeds

## \Delta t = {\frac {\Delta d} {\vec v}}
\\ = {\frac {32m} {0.6m/s}}
\\ = 53.3##

## {\frac {16m} {0.72m/s}}
\\ = 22.2##

It takes her 22 seconds to walk from 16m away versus the 53 seconds it would take her to sail directly there.

Am I correct in any of this?

All except in the last part, you need to add to her walking time, the time it took to cross the river.

I realized that I left out sailing time to add to the walking time about two seconds after I hit post. Thank you for confirming my work.

Also, on part A, you don't really have to take the inverse tangent, then the tangent, again. If you realize that tangent function returns the slope of a line with that angle. The "slope" of the path ( a proportion). You travel 1.2 km South, for every 2.5 km East. So it is (1.2 km) / (2.5 km) = 0.48 [dimensionless] Now we just need to multiply this by the distance (East) across the river, and you will know how far South you moved.

That's how the textbook taught to find the distance: use trigonometry to get the distance and inverse to get the angle. I didn't know your method, but thank you for teaching me that. I don't think I need the inverse angle, but I decided to throw it in my work as the single solitary example problem in the text included it.

1. How do velocity vectors affect navigation across a river?

Velocity vectors are important in understanding the speed and direction of the water in a river. They can help determine the best path to take when navigating across a river, as well as the amount of time it will take to reach a certain destination.

2. What factors affect the velocity vectors of a river?

The velocity vectors of a river can be affected by various factors such as the slope of the river, the shape of the river bed, and the amount of water flow. These factors can change the direction and speed of the water, making it important for navigation purposes.

3. How can one calculate the velocity vectors of a river?

The velocity vectors of a river can be calculated using the equation V= d/t, where V is velocity, d is distance, and t is time. By measuring the distance and time it takes for an object to move across the river, the velocity vectors can be determined.

4. How can velocity vectors be used in navigation across a river?

Velocity vectors can be used to determine the angle and direction of the current in a river. By understanding the speed and direction of the water, a navigator can plan a route that minimizes the effort required to travel across the river.

5. Are velocity vectors the only factor to consider when navigating across a river?

No, velocity vectors are not the only factor to consider when navigating across a river. Other important factors include the width of the river, the presence of obstacles, and the strength of the current. All of these factors must be taken into consideration to ensure safe and efficient navigation.

• Introductory Physics Homework Help
Replies
11
Views
2K
• Introductory Physics Homework Help
Replies
6
Views
6K
• Introductory Physics Homework Help
Replies
1
Views
2K
• Introductory Physics Homework Help
Replies
8
Views
14K
• Introductory Physics Homework Help
Replies
1
Views
4K
• Introductory Physics Homework Help
Replies
4
Views
3K
• Introductory Physics Homework Help
Replies
22
Views
4K
• Introductory Physics Homework Help
Replies
1
Views
2K
• Introductory Physics Homework Help
Replies
21
Views
25K