How Far Is the Crab Nebula from Earth?

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Homework Help Overview

The discussion revolves around calculating the distance from Earth to the Crab Nebula, which is a supernova remnant. Participants are exploring the implications of the nebula's expansion speed, the angle it forms with Earth, and the historical context of its observation.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relationship between the nebula's expansion speed and the distance calculation, questioning the relevance of the angle and the method of using trigonometry. There are attempts to clarify the geometric relationships involved, particularly regarding the triangle formed by the nebula and Earth.

Discussion Status

Several participants are actively engaging with the problem, offering different approaches to the calculations and questioning each other's reasoning. There is a mix of interpretations regarding the use of angles and trigonometric relationships, with no clear consensus yet on the correct method.

Contextual Notes

Participants are operating under the constraints of homework guidelines, which may limit the types of assistance they can provide. There is a noted confusion regarding the application of angular measurements and the significance of the nebula's expansion speed in the context of the problem.

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Homework Statement



Hi.

The Crab Nebula which can be seen with even a small telescope, is the result of a supernova. All parts of the nebula are moving away from the centre at 1.18*10^6 m/s. The angle that the Crab Nebula forms with the Earth is 0.083 degrees. This supernova was observed by chinese astronomers in 1054. You can assume that the Crab Nebula has expanded at a uniform rate since then.

- What is the distance from Earth to Crab Nebula?



Homework Equations



Distance = Speed of light * Time elapsed.

The Attempt at a Solution



I said that there was 2014-1054=960 years since we first observed it. Hence 960 lightyears which is equal to 9.1*10^18 m. However, this is wrong according to the answers (and wikipedia while we're at it). Btw, what do I need the expansion speed for? It's so small compared to c. And what about the angle? Any help is appreciated. Thank you.
 
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Use a bit of trig to figure this out. It always helps to draw a diagram if the problem lends itself to it. Fill the known quantities in on the diagram. Upload it if you are still having problems.
 
I did that already... And I get the same answer... What am I doing wrong?
 
Draw the triangle that the Crab Nebula makes with the earth. Fill in the angle and known distance and upload the image if you can.
 
I don't think it will be much help to you. It's reversed.

Please can't you just tell me what I'm doing wrong?
 

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You can get the diameter, D, of the CN since it has expanding for 960 years using its expansion rate. Together with the angle that D extends at the Earth you can then calculate R, the distance to the CN. Hint: Work in radians.
 
I simply do not understand what you just wrote. The diameter is 2 * 1.18*10^6 m/s * 960 years * 31557600 years/s = 7.15 * 10^16 m. What do I do from here?
 
For an angular measurement, θ, in radians, we have that

θ = s/r

where s is the arc length, D in this case, and r is the radius of the circle, the distance to the CN in this case.
 
How can the radius be the distance from CN to Earth? Isn't the radius simply the radius of crab nebula? And how is the arc length how much CN has expanded the last 960 years?
 
  • #10
The given angle is the angle that the diameter of the nebula subtends at the earth, as you indicated on your diagram. So if we work in radians then the r in the formula above is the distance to the nebula and the arc length, s in the formula, is the diameter of the nebula.
 
  • #11
Couldn't you also say that the radius is the opposite side in the right angled triangle. The adjacent side is the distance from CN to Earth, and the 0.083/2=0.0415 degrees is the angle. Since tan(0.0415) = radius/distance we have that the distance is radius/tan(0.0415). This gives the right answer.
 
  • #12
The methods are equivalent. The angular approach is more common in astronomy where almost everything is measured in angular terms.

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