How Far is the Third-Order Bright Fringe from the Central Maximum?

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SUMMARY

The discussion focuses on calculating the distance from the central maximum to the third-order bright fringe in a double-slit interference pattern. Given parameters include a slit separation of 0.25 mm, a screen distance of 1.5 m, and a light wavelength of 680 nm. The correct approach involves using the formula for fringe spacing, which incorporates the order of the fringe (m=3 for the third-order) and the wavelength. The final calculation yields a distance of approximately 0.51 m from the central maximum to the third-order bright fringe.

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Homework Statement


Monochromatic light passes through 2 narrow slits 0.25mm apart and forms an interference pattern on screen 1.5m away.If light with a wavelength of 680nm is used,what is the distance between center of central maximum and center of the third-order bright fringes?


Homework Equations



sorry don't have..

The Attempt at a Solution


d=0.25mm ,y=1.5m lambda=680x10^-9, central max=0, third order=3
i tried using sin@=m x lambda /d ,but y is given..i think i should have use it but then i don't know where n when to use..can you please hint me?
 
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