How Far Will a Box Slide on a Frictional Surface After Being Pushed?

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SUMMARY

The discussion centers on calculating the distance a box will slide on a frictional surface after being pushed, given a coefficient of kinetic friction of 0.2 and an initial speed of 3.0 m/s. The user applies Newton's second law, stating Fapplied - Ffriction = ma, and attempts to use the kinematic equation Vf^2 = Vo^2 + 2ax. The user realizes that they have too many variables and cannot derive a solution. Ultimately, the user acknowledges a misunderstanding and resolves the issue independently.

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Arbitrary
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In preparing for a test I came across this problem:

A box is given a push so that it slides across the floor. How far will it go, given that the coefficient of kinetic friction is 0.2 and the push imparts an initial speed of 3.0m/s?

Here's what I've come up with so far:

Fapplied - Ffriction = ma

V0=3, x=?, a=?, Vf=0
Vf^2=Vo^2+2ax;
0=3^2+2ax
-9=2ax

I can't come up with any more equations, and there are currently too many variables to put the equations together. It seems pretty straightforward--perhaps I'm just missing something crucial.
 
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*edit
Opps, nvm. :p
 

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