How Far Will a Box Slide Before Stopping on a Frictional Surface?

[PinkFly]

1. Determine the distance it takes for a 25 kg box to stop sliding if it has a speed of 12m/s on a surface with a coefficient of friction of 0.15.



2. W=F*d
Coefficient of friction = Force of friction/Normal Force
Kinetic energy = 1/2*m*v^2



3. With the mass and the coefficient of friction, I got the force of friction.
With the mass and velocity, I got the kinetic energy.
Then I divided the Kinetic energy by the force of friction because the Newton's would cancel out and I would be left with meters.

Is this the right solution? I checked the answer in the back and it is correct but I'm not sure if this was just a coincidence.

 

[Ninty64]

The Kinetic Energy is equal to the work that the friction force must do to stop the box. Since W=Fd, the distance that box travels is d=W/F. So yes, you did it correctly.