How Far Will a Cart Roll on Sand and Gravel? | Work/Energy Question

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SUMMARY

The discussion focuses on the physics problem of determining how far a cart will roll on gravel after rolling through sand. The cart exerts a horizontal force of 6 N on sand, traveling 6 cm before stopping, resulting in a work done of 0.36 J. When encountering gravel, where the cart exerts a force of 9 N, the same work done must apply. The correct calculation shows that the cart will roll 4 cm into the gravel before stopping, confirming that the change in kinetic energy remains constant across both surfaces.

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Homework Statement



A cart is set rolling across a level table, at the same speed
on every trial. If it runs into a patch of sand, the cart exerts
on the sand an average horizontal force of 6 N and travels
a distance of 6 cm through the sand as it comes to a stop.
If instead the cart runs into a patch of gravel on which
the cart exerts an average horizontal force of 9 N, how far
into the gravel will the cart roll before stopping? (a) 9 cm
(b) 6 cm (c) 4 cm (d) 3 cm (e) none of those answers

Homework Equations



w = ΔK.E.

The Attempt at a Solution



I basically found that 6N(.06) = .36 J for the sand part of it and set that answer to 9N * x = .36J and got the right answer but i don't know if i got the right answer because of the right reasons. My thinking was that if the mass and velocity of both carts are the same then the change in kinetic energy is ultimately going to be the same but I'm not to sure about this
 
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you've got the right idea. In both cases, the KE of the cart is the same, so the work done to stop the cart is the same in both cases.
 

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