How Far Will a Skier Land After a Flying Ski Jump?

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SUMMARY

The discussion focuses on calculating the landing distance of a skier after a flying ski jump, with the skier achieving a speed of 110 km/h upon takeoff. The analysis reveals that the horizontal and vertical distances are equal due to the 45-degree slope, leading to a projectile motion problem. The calculated horizontal distance is derived from the initial velocity components, with Vx determined as 30.6 m/s. The discrepancy between theoretical calculations and actual jump distances, which can reach up to 165m, is attributed to factors such as air resistance and friction not being considered in the basic model.

PREREQUISITES
  • Understanding of projectile motion principles
  • Basic knowledge of trigonometry, specifically tangent and cosine functions
  • Familiarity with kinematic equations for motion
  • Concept of vector decomposition in two dimensions
NEXT STEPS
  • Study the effects of air resistance on projectile motion
  • Learn about advanced kinematic equations for varying angles of takeoff
  • Explore the impact of friction on ski jump performance
  • Investigate real-world factors affecting ski jump distances, such as wind conditions
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This discussion is beneficial for physics students, sports scientists, and engineers interested in the dynamics of ski jumping and projectile motion analysis.

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Homework Statement


In a flying ski jump, the skier acquires a speed of 110 km/h by racing down a steep hill and then lifts off into the air from a horizontal ramp. Beyond this ramp, the ground slopes downward at an angle of 45 degrees. (a) Assuming the skier is in a free-fall motion after he leaves the ramp, at what distance down the slope will he land? (b) In actual jumps, skiers reach distances of up to 165m. Why does this not agree with the result you obtained in part (a)?


Homework Equations


vy= voy-gt
y-yo= voyt + 1/2(ayt^2)


The Attempt at a Solution

 
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Since the slope is 45 degrees, horizontal distance and the vertical fall are equal.. Find those quantities and equate them.
 
I thought this looked like a projectile question. The question didn't mention a take of angle so looking at what was given I think that angle is horizontal so its 0 degrees.

You need to vectorise everything two because this is a two dimensional question.
The velocity of take off first- Vx= V Cos theta
= 30.6 m/s
and Vy= V Sin theta
= 0
Then substitute those values into the vector for distance in the x and y plane.
The skier will hit the slopes when distancex/distance y= Tan -45 degrees and you'll find t the time it took to hit the hill.
To find the downhill distance draw a triangle with x distance on the on the horizontal and y distance on the vertical and 50 degrees for their facing angle so x distance /Cos 50 should get you that distance.
I came up with a huge figure. I get friction etc wasn't taken into account,
 

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