How Far Will the Ball Travel Horizontally If Aimed at 33 Degrees?

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SUMMARY

The discussion focuses on calculating the horizontal distance a 20.0 g steel ball bearing will travel when launched at an angle of 33.0 degrees from a compressed spring. The spring propels the ball to a height of 1.35 m when aimed vertically, indicating that the potential energy is converted into kinetic energy. It is established that the spring's internal inertia can be neglected, allowing for a straightforward application of projectile motion equations to determine the horizontal distance traveled.

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  • Understanding of basic physics concepts, particularly projectile motion.
  • Familiarity with energy conservation principles, specifically potential and kinetic energy.
  • Knowledge of trigonometric functions related to angles in projectile motion.
  • Ability to perform calculations involving mass, height, and angles.
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  • Calculate the initial velocity of the ball using the height of 1.35 m and energy conservation principles.
  • Learn how to apply the projectile motion equations to determine horizontal distance.
  • Explore the effects of varying launch angles on projectile distance.
  • Investigate the role of spring constants in energy transfer during launches.
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schrock
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I am convinced I have not received enough info to solve this prob. Please help me get started. A small steel ball bearing with a mass of 20.0 g is on a short compressed spring. When aimed vertically and suddenly released, the spring sends the bearing to a height of 1.35 m. Calculated the horizontal distance the ball would travel if the same spring were aimed 33.0 degrees from the horizontal.
 
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My guess is that you have to assume the spring has no internal inertial so that all of the spring force goes into accelerating the ball. Since it's not included, the problem statement implies that the spring constant doesn't affect the outcome.
 

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