How Fast Are the Cars Moving Toward and Away from Each Other?

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Homework Help Overview

The problem involves two cars moving toward and away from each other, with a focus on determining their speeds based on the rates at which the distance between them changes. The subject area includes concepts from kinematics and relative motion.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the setup of the problem using equations to express the relationships between the cars' velocities and distances. There is an attempt to derive equations based on the given rates of distance change.

Discussion Status

Some participants are actively working through the equations and attempting to clarify the definitions of variables used in the discussion. There is a request for further explanation regarding the variables and their meanings, indicating a collaborative effort to understand the problem better.

Contextual Notes

Participants are navigating the definitions of variables and the relationships between the cars' velocities, with some constraints around the clarity of the initial problem setup and variable definitions.

Phys student
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1:two cars are moving with a constant speed toward each other and the distance between them is decreasing at a rate of 3 m/s if the two cars are moving with the same speed but this time in the same direction the distance between them is decreasing at a rate 1 m/s. what is the speed of each car
2. Homework Equations : D=VT V=vo+at ?
3. The Attempt at a Solution : if they have the same speed then when they are moving toward each other each car's speed must be 1.5 m/s but when i read the second part that idea must be invalid

Can you please give me a hint on how to start guys?
 
Last edited:
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Let car A at left and B on the right.

Please sketch the diagram for better understanding.
Let car A at origin and car B at a distance x from origin
y=at
z=-bt + x, car B is going opposite direction of car A

Distance between them is -(z-y)

s=-t(b+a) +x
Velocity as time derivative of position,
v=-(a+b)
v =-3
b+a=3 ... (1)

For same speed and direction
y=at
z=bt+x

b-a=1 ...(2)

We have 2 equations and 2 unknowns.
 
Last edited:
azizlwl thanks for the reply but can you please explain what do you mean by y,z and s , and does the b and a in the two equations mean the velocity of each car ?
 
Phys student said:
azizlwl thanks for the reply but can you please explain what do you mean by y,z and s , and does the b and a in the two equations mean the velocity of each car ?

Sorry for not defining the variables.
a and b are the velocities for car A and car B respectively.
y and z is displacement of for car A and car B respectively with respect of time.
x is the intial position of Car B whilst car A at origin at t=0.
 

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