How Fast Can You Drive Without Hitting the Deer?

  • Thread starter Thread starter Jennifer001
  • Start date Start date
  • Tags Tags
    Kinematics
Click For Summary
SUMMARY

The maximum speed a driver can maintain without hitting a deer 35 meters ahead, given a reaction time of 0.5 seconds and a maximum deceleration of 10 m/s², is calculated using kinematic equations. The driver must use the equations Xf = Xi + ViT + 1/2aT² and Vf - Vi = aT to establish a relationship between initial speed (Vi) and time (T). Solving these equations reveals that the maximum initial speed (Vi) is 10T, which can be substituted back into the distance equation to find the exact speed required to avoid collision.

PREREQUISITES
  • Understanding of kinematic equations
  • Knowledge of basic physics concepts such as acceleration and deceleration
  • Ability to manipulate algebraic equations
  • Familiarity with units of measurement in physics (meters, seconds)
NEXT STEPS
  • Study kinematic equations in detail, focusing on their applications in real-world scenarios
  • Learn about the effects of reaction time on stopping distances in driving
  • Explore advanced topics in physics such as dynamics and motion analysis
  • Practice solving problems involving deceleration and stopping distances
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as drivers interested in understanding the implications of speed and reaction time on safety.

Jennifer001
Messages
22
Reaction score
0

Homework Statement


you're driving down the highway late one night at 20ms when a deep steps onto the road 35m infront of you. your reaction time before steeping on the brakes is 0.5s and the max deceleration of ur car is 10m/s^2

what is the max speed you could have and still not hit the deer?

deltaX=35m V=?
a=-10m/s^2 reaction time = 0.5s


Homework Equations



Xf= Xi+ViT+1/2aT^2
Vf-Vi=aT
Vf^2=Vi^2+1/2a(deltaX)

The Attempt at a Solution


so this is what i tried

i pluged the numbers into the first equation to get

35=0+ViT+1/2(-10)T^2

and i have 2 missing variables so i tried to get it from the other equation

Vf-Vi=aT
0-Vi=(-10)T then that didnt work so i tried the other equation

Vf^2=Vi^2+1/2a(deltaX)
0=Vi^2+1/2(-10)35
Vi= 13.23m/s

and i know that Vi can't be right because i did the question before it and it had Vi of 20m/s and it was 5m from hitting the deer...i don't know what i did wrong can someone help please?
 
Physics news on Phys.org
Jennifer001 said:

Homework Statement


you're driving down the highway late one night at 20ms when a deep steps onto the road 35m infront of you. your reaction time before steeping on the brakes is 0.5s and the max deceleration of ur car is 10m/s^2

what is the max speed you could have and still not hit the deer?

deltaX=35m V=?
a=-10m/s^2 reaction time = 0.5s


Homework Equations



Xf= Xi+ViT+1/2aT^2
Vf-Vi=aT
Vf^2=Vi^2+1/2a(deltaX)

The Attempt at a Solution


so this is what i tried

i pluged the numbers into the first equation to get

35=0+ViT+1/2(-10)T^2

and i have 2 missing variables so i tried to get it from the other equation

Vf-Vi=aT
0-Vi=(-10)T then that didnt work so i tried the other equation

Vf^2=Vi^2+1/2a(deltaX)
0=Vi^2+1/2(-10)35
Vi= 13.23m/s

and i know that Vi can't be right because i did the question before it and it had Vi of 20m/s and it was 5m from hitting the deer...i don't know what i did wrong can someone help please?
In order to JUST miss hitting the deer, it must take all 35 meters to slow to 0 m/s. So you have TWO of the equations you just gave: 35=0+ViT+1/2(-10)T^2 for the 35 m and 0-Vi=(-10)T for the time to slow to 0. Now you have two equations in the two "unknown" numbers Vi and T. 0-Vi= -10T tells you that Vi= 10T. Replace Vi by that in the first equation to get a simple equation for T alone. Once you have found T, put that into Vi= 10T to find Vi.

 

Similar threads

Replies
20
Views
3K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 2 ·
Replies
2
Views
5K
Replies
5
Views
5K
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 1 ·
Replies
1
Views
3K