How Fast Do Bacteria Multiply in a Culture?

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Homework Help Overview

The discussion revolves around a problem concerning bacterial growth in a culture, specifically focusing on the mathematical modeling of population growth using an exponential function. Participants are tasked with determining the population size after specific time intervals based on a doubling rate.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore the derivation of the constant k from the given population growth formula and question the initial population size after a specified time. There is also a discussion about the implications of the time frame on the population size.

Discussion Status

The conversation is ongoing, with participants clarifying the steps involved in calculating k and addressing the implications of the time intervals on the population size. Some participants are questioning the assumptions made regarding the doubling time and its effect on the calculations.

Contextual Notes

There is a focus on the specific time intervals of 40 minutes and 10 hours, with participants noting the need to clarify the calculations before proceeding to find the population sizes at those times. The original poster's inquiry about the derivation of a specific value indicates a potential gap in understanding the exponential growth model.

Niaboc67
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A bacteria culture initially contains 2000 bacteria and doubles every half hour. The formula for the population is p(t)=2000 e^{kt} for some constant k. (You will need to find k to answer the following.)

Find the size of the baterial population after 40 minutes.

Find the size of the baterial population after 10 hours.

Soltn:
When t = 0.5 hour, p(t) = 4000, so we have

4000 = 2000e^(0.5k)

2 = e^(0.5k)

ln(2) = 0.5k

k = ln(2)/0.5 = 1.386294361

Where did 4000 part come from?

Thank you
Where
 
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Niaboc67 said:
A bacteria culture initially contains 2000 bacteria and doubles every half hour. The formula for the population is p(t)=2000 e^{kt} for some constant k. (You will need to find k to answer the following.)

Find the size of the baterial population after 40 minutes.

Find the size of the baterial population after 10 hours.

Soltn:
When t = 0.5 hour, p(t) = 4000, so we have

4000 = 2000e^(0.5k)

2 = e^(0.5k)

ln(2) = 0.5k

k = ln(2)/0.5 = 1.386294361

Where did 4000 part come from?

Thank you
Where
A bacteria culture initially contains 2000 bacteria and doubles every half hour.
 
@SteamKing but it's 40 minutes so shouldn't it be a little more than that?
 
Niaboc67 said:
@SteamKing but it's 40 minutes so shouldn't it be a little more than that?

No. You are still just working out the value of k. You have not gotten to the 40 minute problem yet.
 

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