1. The problem statement, all variables and given/known data and after 3 hours there are 600 bacteria. Assuming bacteria grow at rate proportinal to their size, which means you can use the function, y=Aekt, where y is the number of bacteria and t is time in hours. 1) find the number of bacteria after 5 hours, 2) when will the population reach 2,000? 2. Relevant equations 3. The attempt at a solution First, find k: 600=300e3k 2=e3k k=1/3*ln(2)=0.231 1) y=300e5*0.231=952.207 2) 2000=300e0.231t 6.667=e0.231t t=1/0.231 ln (6.667)=8.21 Please check my answers. J.