How Fast Does a Ship Travel to Reach the Nearest Star in 4.25 Years?

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Homework Help Overview

The discussion revolves around calculating the speed of a ship traveling to the nearest star, which is approximately 4.5 light-years away, and reaching it in 4.25 years according to the ship's onboard clock. The problem involves concepts from special relativity, including Lorentz transformations and length contraction.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore different methods for solving the problem, including the Lorentz transformation and length contraction. Some question the setup of events necessary for applying these transformations, while others attempt to derive speed using the length contraction formula.

Discussion Status

There are multiple approaches being discussed, with some participants providing calculations and results. However, there is no explicit consensus on the correct speed, as different values have been proposed, and participants are encouraged to share their work for verification.

Contextual Notes

Participants note the importance of defining events clearly when using Lorentz transformations and the potential for misinterpretation when applying length contraction. The discussion reflects the complexity of the problem and the need for careful consideration of the variables involved.

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Homework Statement


According to observations on Earth, the distance to nearest star is 4.5 light-years. A ship which leaves Earth takes 4.25 years (according to onboard clock) 4.25 years to reach this star. Calculate the speed at which this ship travels.


Homework Equations


(I think)
x' = [tex]\gamma[/tex](x-ut)
t' = [tex]\gamma[/tex](t-ux/c2)
L = L0/[tex]\gamma[/tex]

The Attempt at a Solution


so we know:
x = 4.25 light years, and, t' = 4.25 years.
using length contraction, L (or x') = 4.25 / [tex]\gamma[/tex]]

So i tried using this in x = [tex]\gamma[/tex](x' + ut') but only managed to get 0 = [tex]\gamma[/tex]ut'.

I can't find any other way of reducing variables to obtaining new variables and would love a push in the right direction.

Thanks in advance.
 
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If you want to do this question the Lorentz transformation way, you need to have 2 events, one being leaving Earth, and one being arriving at the star.

So event 1: (x,t)=(0,0) (x',t')=(0,0) so that your coordinates are synchronized at the point of departure. This step is sometimes implicit, but you should account for this for completeness.

Event 2: (x,t)=(4.5ly, ?) (x',t')=(0,4.25years)

Your job is then to use the transforms to get the question mark. In the end v=x/t.

A simpler way to answer this IMO, is to just use length contraction. You know that L'=L/gamma. Speed v, then is just v=L'/t'=L/gamma*t'. Gamma has a v in it as well, and you can solve for v.

This method requires you to keep track of what exactly L and L' mean, and what exactly you are trying to solve for. It can be misused...but it's simpler than using the Lorentz transforms.
 
Using the length contraction method, I managed to get:

v = [tex]\frac{1}{\sqrt{2}}[/tex]c

Any chance of confirmation?
 
Let's see:

L=4.5ly t'=4.25 years

[tex]v=\frac{L}{\gamma t'}=\frac{L\sqrt{1-\frac{v^2}{c^2}}}{t'}[/tex]

[tex]v^2=\frac{L^2(1-\frac{v^2}{c^2})}{t'^2}[/tex]

Solving for v, I get: v=.529c which doesn't seem to match yours. Perhaps you can show your work?
 

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