How Fast Does a Spaceship Travel from Earth to Pluto and Back in 11 Hours?

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SUMMARY

The discussion centers on calculating the speed of a spaceship traveling from Earth to Pluto and back in 11 hours, with the journey to Pluto taking 5 hours each way. The key equations used include speed = distance/time and the time dilation formula (1-v)^1/2 (change in t from a to b) = proper time. Participants noted that the problem assumes a constant speed and that the distance to Pluto is effectively 5 light-hours, indicating the use of units where the speed of light (c) equals 1. This leads to the conclusion that the spaceship's speed must be calculated in relation to light speed.

PREREQUISITES
  • Understanding of basic physics concepts, particularly speed and time dilation.
  • Familiarity with the equation for speed: speed = distance / time.
  • Knowledge of special relativity, specifically the time dilation formula.
  • Ability to work with units where the speed of light (c) is normalized to 1.
NEXT STEPS
  • Study the implications of special relativity on time and speed calculations.
  • Learn about the concept of light-years and how to convert distances into time at light speed.
  • Explore the derivation and application of the time dilation formula in various scenarios.
  • Investigate real-world applications of constant speed travel in space missions.
USEFUL FOR

Students in physics, particularly those studying special relativity, as well as educators and anyone interested in the calculations involved in space travel and time measurement at relativistic speeds.

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Homework Statement



A spaceship leaves earth, travels to Pluto (which os 5 hours of distance away at the time), and then returns to Earth in exactyly 11 hours later. assume the spaceships acceleration time is very short so it is always traveling at a constant speed. also assume that Earth and pluto are approximately at rest to each other and the sun during the journey.

a- what is the speed of the ship during each part of the journey?
b- calculate the time measured by the ships clock during the entire trip.

Homework Equations


speed= distance / time

(1-v)^1/2 (change in t from a to b)= proper time

The Attempt at a Solution



I'm not sure what to do because i don't understand how the spaceshp can travel at a constant speed and take 5 hours to get there and 5 hours to get back. I am missing something.
 
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Since you wrote sqrt(1-v^2) it looks like you are working in units where the speed of light c=1. Then to say Pluto is 5 hrs away really means that it's (5hrs)*c away or 5 hours traveling at the speed of light. When working in units where c=1, you are sort of allowed to be sloppy and drop factors of c.
 

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