How Fast Does a Trebuchet Counterweight Travel?

Click For Summary
SUMMARY

The forum discussion centers on calculating the speed and travel time of a 2000 lbs counterweight in a trebuchet after specific distances of 1 inch, 60 inches, and 120 inches. The calculations utilize the formula v = sqrt(2gh), where g is the acceleration due to gravity (9.8 m/s²) and h is the height in meters. The results indicate maximum speeds of 2.3 feet per second at 1 inch, 18 feet per second at 60 inches, and 25 feet per second at 120 inches, with corresponding minimum travel times of 0.072 seconds, 0.56 seconds, and 0.79 seconds, respectively. Users are advised to use Google for quick calculations or Excel with specific formulas for varying distances.

PREREQUISITES
  • Understanding of basic physics principles, particularly kinetic energy and gravitational force.
  • Familiarity with the formula v = sqrt(2gh) for calculating velocity.
  • Basic knowledge of using Excel for mathematical calculations.
  • Awareness of unit conversions between feet and inches.
NEXT STEPS
  • Research the use of trebuchet simulators for practical applications and design testing.
  • Learn how to implement unit conversions in Excel for accurate calculations.
  • Explore advanced physics concepts related to projectile motion and energy loss due to friction.
  • Investigate the design specifications of different trebuchet models for optimized performance.
USEFUL FOR

Engineers, physics enthusiasts, hobbyists building mechanical launching devices, and anyone interested in the mechanics of trebuchets and projectile motion.

dalebennett
Messages
4
Reaction score
0
Hey Smart Guys,

At age 61, I am building a mechanical launching device (Trebuchet) and I need to know how fast my counterweight will be traveling.

How fast will it be traveling after 1 inch
How fast will it be traveling after 60 inch
How fast will it be traveling after 120 inch

Also, please provide the travel time to reach each point (1, 60 & 120 in.)

The counterweight surface is flat, weighs 2000 lbs with a square surface area of 1296 Sq Inches. (3'x3')

I don't do formulas very well, so plain English would be much appreciated!

Thanks in Advance,

Dale
 
Last edited:
Physics news on Phys.org
dalebennett said:
Hey Smart Guys,

At age 61, I am building a mechanical launching device (Trebuchet) and I need to know how fast my counterweight will be traveling.

How fast will it be traveling after 1 inch
How fast will it be traveling after 60 inch
How fast will it be traveling after 120 inch

Also, please provide the travel time to reach each point (1, 60 & 120 in.)

The counterweight surface is flat, weighs 2000 lbs with a square surface area of 1296 Sq Inches. (3'x3')

I don't do formulas very well, so plain English would be much appreciated!

Thanks in Advance,

Dale

Fg=Ek

Force of gravity will convert to Kenetic energy

mgh=1/2mv^2

solve for v
(Devide both sides by m, multiply by 2 and sq rt both sides)

v=sqrt/ 2gh

EDIT: g=gravity at 9.8m/s and h is height in meters and v is also in meters/second

When you find speed you already have distance

v=d/t

t=vd

Multiply the speed in m/s and distance in meters to get the time
 
There will be some energy lost to friction so the above analysis gives a high estimate. If you need better you will need to figure out a way to measure the velocity.
 
I'm sorry, but I don't understand these equations. Would you be kind enough to do the actual calculation. I flunked out of algebra.
 
The answer depends on what kind of trebuchet you want to build. In addition, you need to specify things like the length, weight and shape of the beam and where the axle is in relation to both the counterweight and payload.
 
Actually, I just want to use this information as a reference point. For now, all I need are the raw answers. Please, just disregard the Trebuchet design for now. If you are interested in this project, I would be extremely interested in providing you more detail a little later.

This is a new concept for a Trebuchet and there are many physics questions that will need to be answered. For now, just the basic math, please.

I'm planning a 1 mile launch that has never been done before.
 
I copy/pasted that equation exactly as show into Excel and it did NOTHING.

Is '1 inch' suppose to be embedded into the equation?

What value do I change. I'm am truly sorry for my ignorance.

Can you give it EXACTLY as it should be put into an excel cell - for 1 in and 2 inches - then I will know how to modify the equation for any distance?

the following was the last thing I tried.

=sum(sqrt(2*(9.8(m/(s^2)))*1))

Obviously, I don't know what I'm doinh

Thanks for your patience.

Dale
 
http://www.uni-siegen.de/fb11/nm/aktuelles/downloads/trebuchet_adams.pdf

This might be useful for you, in particular the model described in figure 5(c).
 
Last edited by a moderator:
  • #10
In the absence of any design specifications the best you can do is set limits for speed and time based on a free falling counterweight.

For what it's worth, here's what you get for the numbers:

1 inch: Max speed = 2.3 feet per second, Min time = 0.072 seconds
60 inch: Max speed = 18 feet per second, Min time = 0.56 seconds
120 inch: Max speed = 25 feet per second, Min time = 0.79 seconds
 
  • #11
dalebennett said:
I copy/pasted that equation exactly as show into Excel and it did NOTHING.

That wasn't intended to be used in excel. Google has a built in calculator that understands units and constants. If you click the link you should see 1 inch gives an answer of 1.578 mph. If you want to change the distance you do so in the Google search box. You should notice that if you, for example, change 1 inch to 3 feet the answer pops up in a box directly below the search box. You don't even have to click search.

If you want to use excel the formulas should be:
Code:
=SQRT(2 * 32.174 * 1) <- one [B]foot[/B], answer is 8.02 [B]feet[/B] per second
=SQRT(2 * 32.174 * 2) <- two [B]feet[/B], answer is 11.34 [B]feet[/B] per second
=SQRT(2 * 386.09 * 1) <- one [B]inch[/B], answer is 27.79 [B]inches[/B] per second
=SQRT(2 * 386.09 * 2) <- two [B]inches[/B], answer is 39.3 [B]inches[/B] per second
Pay careful attention to the difference between inches and feet in the above forumulas. Like I said, Google understands units and does the conversions for you. Excel does not, and you have to manually do the conversions.
 
  • #12
There's a trebuchet simulator that is probably more useful for you:

http://www.trebuchet.com/sim/
 
Last edited by a moderator:

Similar threads

Replies
3
Views
2K
  • · Replies 41 ·
2
Replies
41
Views
4K
  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 9 ·
Replies
9
Views
4K