How Fast Does a Trebuchet Counterweight Travel?

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Discussion Overview

The discussion revolves around calculating the speed and travel time of a counterweight in a trebuchet, focusing on specific distances (1 inch, 60 inches, and 120 inches). Participants explore various methods and equations to estimate these values, while also addressing the complexities involved in the design and operation of the trebuchet.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Mathematical reasoning
  • Homework-related

Main Points Raised

  • One participant, Dale, requests the speed and travel time of the counterweight at specified distances, expressing a preference for plain language over formulas.
  • Another participant provides a formula relating gravitational potential energy to kinetic energy, suggesting that speed can be calculated using the equation v=sqrt(2gh), where g is the acceleration due to gravity and h is the height.
  • Some participants note that energy loss due to friction may affect the accuracy of the calculations, indicating that the initial analysis may yield high estimates.
  • One participant emphasizes that the specific design of the trebuchet, including dimensions and weight distribution, will influence the results and should be considered for more accurate calculations.
  • Dale expresses a desire for raw answers without delving into design specifics, indicating that he is working on a novel concept for a trebuchet.
  • Several participants attempt to clarify how to input calculations into Excel, with one providing specific formulas for different distances and noting the importance of unit conversions.
  • Links to external resources, including a trebuchet simulator and a PDF model, are shared for additional reference.
  • Another participant suggests that without design specifications, the best estimates can be derived from a free-falling counterweight model, providing maximum speeds and minimum times for the specified distances.

Areas of Agreement / Disagreement

Participants express a range of views on the calculations and the impact of design specifics, indicating that multiple competing perspectives exist. There is no consensus on the exact calculations or the implications of design choices.

Contextual Notes

Some participants highlight limitations related to assumptions about energy loss, the need for precise design specifications, and the differences in unit conversions when using various calculation methods.

Who May Find This Useful

This discussion may be useful for individuals interested in mechanical engineering, physics, or those involved in building trebuchets or similar mechanical devices.

dalebennett
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Hey Smart Guys,

At age 61, I am building a mechanical launching device (Trebuchet) and I need to know how fast my counterweight will be traveling.

How fast will it be traveling after 1 inch
How fast will it be traveling after 60 inch
How fast will it be traveling after 120 inch

Also, please provide the travel time to reach each point (1, 60 & 120 in.)

The counterweight surface is flat, weighs 2000 lbs with a square surface area of 1296 Sq Inches. (3'x3')

I don't do formulas very well, so plain English would be much appreciated!

Thanks in Advance,

Dale
 
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dalebennett said:
Hey Smart Guys,

At age 61, I am building a mechanical launching device (Trebuchet) and I need to know how fast my counterweight will be traveling.

How fast will it be traveling after 1 inch
How fast will it be traveling after 60 inch
How fast will it be traveling after 120 inch

Also, please provide the travel time to reach each point (1, 60 & 120 in.)

The counterweight surface is flat, weighs 2000 lbs with a square surface area of 1296 Sq Inches. (3'x3')

I don't do formulas very well, so plain English would be much appreciated!

Thanks in Advance,

Dale

Fg=Ek

Force of gravity will convert to Kenetic energy

mgh=1/2mv^2

solve for v
(Devide both sides by m, multiply by 2 and sq rt both sides)

v=sqrt/ 2gh

EDIT: g=gravity at 9.8m/s and h is height in meters and v is also in meters/second

When you find speed you already have distance

v=d/t

t=vd

Multiply the speed in m/s and distance in meters to get the time
 
There will be some energy lost to friction so the above analysis gives a high estimate. If you need better you will need to figure out a way to measure the velocity.
 
I'm sorry, but I don't understand these equations. Would you be kind enough to do the actual calculation. I flunked out of algebra.
 
The answer depends on what kind of trebuchet you want to build. In addition, you need to specify things like the length, weight and shape of the beam and where the axle is in relation to both the counterweight and payload.
 
Actually, I just want to use this information as a reference point. For now, all I need are the raw answers. Please, just disregard the Trebuchet design for now. If you are interested in this project, I would be extremely interested in providing you more detail a little later.

This is a new concept for a Trebuchet and there are many physics questions that will need to be answered. For now, just the basic math, please.

I'm planning a 1 mile launch that has never been done before.
 
I copy/pasted that equation exactly as show into Excel and it did NOTHING.

Is '1 inch' suppose to be embedded into the equation?

What value do I change. I'm am truly sorry for my ignorance.

Can you give it EXACTLY as it should be put into an excel cell - for 1 in and 2 inches - then I will know how to modify the equation for any distance?

the following was the last thing I tried.

=sum(sqrt(2*(9.8(m/(s^2)))*1))

Obviously, I don't know what I'm doinh

Thanks for your patience.

Dale
 
http://www.uni-siegen.de/fb11/nm/aktuelles/downloads/trebuchet_adams.pdf

This might be useful for you, in particular the model described in figure 5(c).
 
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  • #10
In the absence of any design specifications the best you can do is set limits for speed and time based on a free falling counterweight.

For what it's worth, here's what you get for the numbers:

1 inch: Max speed = 2.3 feet per second, Min time = 0.072 seconds
60 inch: Max speed = 18 feet per second, Min time = 0.56 seconds
120 inch: Max speed = 25 feet per second, Min time = 0.79 seconds
 
  • #11
dalebennett said:
I copy/pasted that equation exactly as show into Excel and it did NOTHING.

That wasn't intended to be used in excel. Google has a built in calculator that understands units and constants. If you click the link you should see 1 inch gives an answer of 1.578 mph. If you want to change the distance you do so in the Google search box. You should notice that if you, for example, change 1 inch to 3 feet the answer pops up in a box directly below the search box. You don't even have to click search.

If you want to use excel the formulas should be:
Code:
=SQRT(2 * 32.174 * 1) <- one [B]foot[/B], answer is 8.02 [B]feet[/B] per second
=SQRT(2 * 32.174 * 2) <- two [B]feet[/B], answer is 11.34 [B]feet[/B] per second
=SQRT(2 * 386.09 * 1) <- one [B]inch[/B], answer is 27.79 [B]inches[/B] per second
=SQRT(2 * 386.09 * 2) <- two [B]inches[/B], answer is 39.3 [B]inches[/B] per second
Pay careful attention to the difference between inches and feet in the above forumulas. Like I said, Google understands units and does the conversions for you. Excel does not, and you have to manually do the conversions.
 
  • #12
There's a trebuchet simulator that is probably more useful for you:

http://www.trebuchet.com/sim/
 
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