How Fast Does an Arrow Travel When Shot Horizontally?

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SUMMARY

The problem involves calculating the initial velocity of an arrow shot horizontally from a height of 1.5 meters, landing 33 meters away. The time taken for the arrow to hit the ground is determined using the equation y = 0.5(-9.8)t², resulting in a time of approximately 0.553 seconds. This time is then used to find the horizontal velocity, which is calculated as distance divided by time. The final result indicates that the initial velocity of the arrow is approximately 59.7 m/s.

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runningirl
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please help! projectile motion question

Homework Statement



You have a friend who is an archer and she wants to know how fast the arrows leave her bow. You have her launch an arrow horizontally, 1.5 m above the ground, and find that the arrow lands 33 m away. What is the initial velocity of the arrow as it leaves the bow?

Homework Equations



y=.5(-9.8)t^2

The Attempt at a Solution



i don't know where to start with this problem. I'm sorry :(
 
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This is a two stage problem. You first have to find the time it takes the arrow to reach the ground vertically. Then you can use that time to calculate the inital velocity of the arrow horizontally.
 


runningirl said:

Homework Statement



You have a friend who is an archer and she wants to know how fast the arrows leave her bow. You have her launch an arrow horizontally, 1.5 m above the ground, and find that the arrow lands 33 m away. What is the initial velocity of the arrow as it leaves the bow?

Homework Equations



y=.5(-9.8)t^2

The Attempt at a Solution



i don't know where to start with this problem. I'm sorry :(
Yf=Yo+Voy-.5gt^2
=1.5+0-4.9t^2
1.5/4.9=t^2
t=0.553 seconds
...
 

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