How Fast Does Water Exit the Sprinkler Holes According to Bernoulli's Equation?

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SUMMARY

The discussion focuses on calculating the speed at which water exits the holes of a lawn sprinkler using Bernoulli's Equation. Given a garden hose with an internal diameter of 1.75 cm and a water speed of 2 m/s, the sprinkler has 24 holes, each with a diameter of 0.05 cm. The correct approach involves applying the principle of conservation of mass, specifically the equation of continuity, to determine the exit speed of water from the holes, which is approximately 9.6 m/s. The density of water at 10°C is noted as 999.7026 kg/m³, which is relevant for further calculations.

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  • Understanding of Bernoulli's Equation
  • Knowledge of the equation of continuity in fluid dynamics
  • Familiarity with basic fluid properties, including density
  • Ability to perform calculations involving cross-sectional areas
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  • Explore the effects of hole diameter on fluid exit speed
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Students studying fluid dynamics, engineers designing irrigation systems, and anyone interested in the practical applications of Bernoulli's Equation in real-world scenarios.

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Homework Statement



A garden hose having internal diameter of 1.75cm is connected to a lawn sprinkler that consists merely of an enclosure with 24 holes each , each 0.05cm in diameter. If the water in the hose has a speed of 2m/s, at what speed does it leave the sprinkler holes ?

Homework Equations



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The Attempt at a Solution



I think the 24 holes will be multiplied with 0.05 in order to get the total speed and then later dividing it by 24 to get a single hole speed . But we don't know the density? Stumped !
 
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Perhaps You have to look up at the density of water? \rho = 999.7026 kg/m3 at T = +10 C
 

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