How Fast Must a Volleyball Be Served to Clear the Net and Land Inbounds?

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SUMMARY

The discussion focuses on calculating the initial velocity required for a volleyball to clear the net and land inbounds during a jump serve. The net height for women's volleyball is 2.24 m, and the player strikes the ball at 3.05 m, with a horizontal distance of 8.3 m from the net. The formula used is V(o) = R x sqrt(g/(2h)), where h is the height difference (0.81 m). The calculated minimum initial velocity to clear the net is approximately 16.54 m/s.

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Homework Statement



For women's volleyball the top of the net is 2.24 m above the floor and the court measures 9.0 m on each side of the net. Using a jump serve, a player strikes the ball at a point that is 3.05 m above the floor and a horizontal distance of 8.3 m from the net.

(a) If the initial velocity of the ball is horizontal, what minimum magnitude must it have if the ball is to clear the net?

(b) What maximum magnitude can it have if the ball is to strike the floor inside the back line on the other side of the net?




Homework Equations



V(o)=R x sqrt(g/2h)

The Attempt at a Solution



My wild attempt
H in relation to the top of the net = 3.05m - 2.24m = 0.81m
V(o)= 8.3 x sqrt(9.8/2 x .81) = 16.54
 
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noeinstein said:

Homework Statement



For women's volleyball the top of the net is 2.24 m above the floor and the court measures 9.0 m on each side of the net. Using a jump serve, a player strikes the ball at a point that is 3.05 m above the floor and a horizontal distance of 8.3 m from the net.

(a) If the initial velocity of the ball is horizontal, what minimum magnitude must it have if the ball is to clear the net?

(b) What maximum magnitude can it have if the ball is to strike the floor inside the back line on the other side of the net?

Homework Equations



V(o)=R x sqrt(g/2h)

The Attempt at a Solution



My wild attempt
H in relation to the top of the net = 3.05m - 2.24m = 0.81m
V(o)= 8.3 x sqrt(9.8/2 x .81) = 16.54
Mostly correct, but V(o)=R x sqrt(g/(2h))

or v_0\,=\,R\sqrt{\frac{g}{2h}}
 
Thank you much sir for your time!
 

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