How Fast Was the Car Going Before Skidding to a Stop?

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Homework Help Overview

The discussion revolves around a dynamics problem involving a car that skids to a stop after narrowly avoiding a washed-out bridge. Participants are tasked with determining the initial velocity of the car given its mass, the coefficient of friction, and the length of the skid marks.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the forces acting on the car, including gravitational force and frictional force, and how these relate to the car's acceleration and initial velocity. There are attempts to clarify the direction of net force and acceleration, as well as the appropriate equations to use for solving the problem.

Discussion Status

The conversation includes various attempts to analyze the forces and equations involved. Some participants are questioning the assumptions about the direction of forces and the signs of acceleration, while others suggest reviewing kinematic equations to find the initial velocity. There is an ongoing exploration of the relationships between the forces and the resulting motion.

Contextual Notes

Participants note the importance of the braking force and the length of the skid marks, indicating that these factors are crucial for solving the problem. There is also mention of needing to clarify the meaning of symbols used in the equations to avoid confusion.

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Dynamics physics urgent help please!

Homework Statement



A 1350 kg car narrowly avoids running off of a washed out bridge. The coefficient of friction between the car and the road is 0.55. If the skid marks are 100 meters long, what was the initial velocity of the car?


Homework Equations



Fg = mg
Ff = coefficient x Fn

The Attempt at a Solution



Find Fg
Find Ff
Find acceleration
Find final velocity
 
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shubham1 said:

Homework Statement



A 1350 kg car narrowly avoids running off of a washed out bridge. The coefficient of friction between the car and the road is 0.55. If the skid marks are 100 meters long, what was the initial velocity of the car?


Homework Equations



Fg = mg
Ff = coefficient x Fn

The Attempt at a Solution



Find Fg
Find Ff
Find acceleration
Find final velocity
shubham1, you'll have to show a bit more of an attempt. What have you tried? Show us what you've tried so we can know how to help you.
 


d = 100m
v = 0 m/s (final)
u = ? m/s (initial)

a = Look in your book for an equation relating the coefficient of friction to the mass of the object.

What is one of the kinematic equations you know relating acceleration, displacement, and velocities?
 


Important info I forgot to mention: Applied braking force is 9500 N.
I am not sure which way is the Fnet.
I found Fg, which is 13230 N downwards.
I found Ff which is 7276.50 backwards.
I found acceleration which is 12.427 N backwards.
However, my teacher told me to make the Fnet positive, but which way is the Fnet? Is it where the friction is? and also, is the Fa opposite to the Ff.
 


Fnet is probably the net force, which is going forwards. The braking force is what is slowing down the car, which is why your acceleration is going to be negative, as you said you found acceleration to be "backwards". So if acceleration is going this way <--- and is negative, and Fnet should be positive, it should be going ---> this way.
 


Fnet=ma
If a is negative (backwards), then shouldn't Fnet also be negative.
 


I think you're going to have write out what these symbols mean before it gets confusing.

This isn't as complicated as it looks, have you first considered the equation you will be using to solve for the initial velocity? When you know what equation you will use, it will be a lot clearer.
 


For sloving initial velocity, I will use Vf^2 = Vi^2 + 2ad
 


Acceleration = F/m

Where F = frictional force.

You claimed your acceleration was 12N backwards, how did you get 12 Newtons for acceleration? The unit for acceleration is not Newtons.
 
  • #10


Sorry, I meant 12.427 m/s^2 backwards.

I basically did:

Fnet = Fa + Ff (sum of all the forces)
ma = -Fa - Ff
(1350)(a) = -9500-7276.50
a = -12.427 m/s^2 backwards
 
  • #11


If the skid marks are 100 meters long,

You are not using this data
 

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