How Fast Will the Elevator Rise with 14kW of Power?

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SUMMARY

The discussion centers on calculating the constant speed at which an elevator with a mass of 1100 kg can rise when powered by a motor producing 14 kW. The relevant equations include power (P = E / T) and kinetic energy (Ek = mv² / 2). By recognizing that power is the rate of work done (P = W/t) and that work (W) equals force (F) multiplied by distance (d), participants can derive a new equation for power using the given parameters. This approach simplifies the problem and leads to a clear solution for the elevator's speed.

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  • Understanding of basic physics concepts such as power, work, and energy.
  • Familiarity with the equations for power (P = E / T) and kinetic energy (Ek = mv² / 2).
  • Knowledge of force and its relationship to mass and acceleration.
  • Ability to manipulate equations to derive new relationships.
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  • Study the relationship between power, work, and force in mechanical systems.
  • Learn how to apply Newton's second law (F = ma) in practical scenarios.
  • Explore the concept of energy conservation in mechanical systems.
  • Investigate real-world applications of elevator mechanics and motor power ratings.
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Students studying physics, particularly those interested in mechanics, engineers working on elevator systems, and anyone looking to understand the principles of power and motion in mechanical applications.

blarginsnarf
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I'm only in high school physics so this may seem easy to you all XD

Homework Statement


The motor for an elevator can produce 14kW of power. The elevator has a mass of 1100kg, including its contents. At what constant speed will the elevator rise?

Homework Equations


P = E / T?
Ek = mv^2 / 2

The Attempt at a Solution



14000 = E / T
Ek = 1100v^2 / 2
 
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blarginsnarf said:
I'm only in high school physics so this may seem easy to you all XD

Homework Statement


The motor for an elevator can produce 14kW of power. The elevator has a mass of 1100kg, including its contents. At what constant speed will the elevator rise?


Homework Equations


P = E / T?
Ek = mv^2 / 2


The Attempt at a Solution



14000 = E / T
Ek = 1100v^2 / 2

If you use the fact that the power is the rate at which work is done by the motor (P = W/t), and that W = Fd, you can derive a whole new equation for power that consists of only quantities that are mentioned in the problem.
 

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