How he concluded that?Spivak's calculus

[Andrax]

Homework Statement

So the question is : Find all continious functions such that $\displaystyle \int_{0}^{x} f(t) \, \mathrm{d}t$= ((f(x)^2)+C , what interests me is the way the solutions book presented the solution , not the solution itself .
in the solution , it starts with this , clrealy f^2 is differentiable at every point ( it's derivative at x is f(x) ) So **f is differentiable at x whenever **f(x)=/=0****? I have no idea how that can be concluded , this is from Spivak's calculus , if you diffrentiate by the ftc it's clearly f(x)=f(x)f'(x)
but he said that before even giving this formula, the differentiablity of f^2 doesn't have a relation with f(x)=/=0
EDIT : I know that f(x)=f(x)f'(x) What i don't inderstand is this 'clrealy f^2 is differentiable at every point ( it's derivative is f) So f(x)=/=0" why f(x) mustn't equal 0?

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Homework Equations

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Homework Statement

 

[ehild]

f(x)=0 is also a function, and solution of the problem. But there is also an other "non-trivial" solution.

ehild

 

[Andrax]

f(x)=0 is also a function, and solution of the problem. But there is also an other "non-trivial" solution.

ehild

so when he wrotes whenever f(x)=/=0 he mean't the function f(x)=0 not the points where f(x)=0?it makes sense now

 

[ehild]

so when he wrotes whenever f(x)=/=0 he mean't the function f(x)=0 not the points where f(x)=0?it makes sense now

Yes, he wants to find the solution not identically zero.

ehild

 

[LCKurtz]

Homework Statement

So the question is : Find all continious functions such that $\displaystyle \int_{0}^{x} f(t) \, \mathrm{d}t$= ((f(x)^2)+C ,

Does that mean $(f(x))^2$ or $f(x^2)$? I'm guessing the first.

what interests me is the way the solutions book presented the solution , not the solution itself .
in the solution , it starts with this , clrealy f^2 is differentiable at every point ( it's derivative at x is f(x) ) So **f is differentiable at x whenever **f(x)=/=0****? I have no idea how that can be concluded , this is from Spivak's calculus , if you diffrentiate by the ftc it's clearly f(x)=f(x)f'(x)
but he said that before even giving this formula, the differentiablity of f^2 doesn't have a relation with f(x)=/=0
EDIT : I know that f(x)=f(x)f'(x)

But $f(x)f'(x)$ is not the derivative of $f^2(x)$. Am I missing something here?