How High Does a Basketball Bounce After Losing 20% Energy?

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SUMMARY

A basketball dropped from a height of 2 meters loses 20% of its energy upon bouncing due to air friction. The initial potential energy (PE) is calculated using the formula PE = mgh, where g is 9.8 m/s². After losing 20% of its energy, the remaining energy can be expressed as 80% of the initial potential energy, leading to the equation mgh1 = 0.80(mgh) + mgh2. This allows for the calculation of the height of the first bounce (h2).

PREREQUISITES
  • Understanding of potential energy (PE) and kinetic energy (KE)
  • Familiarity with the equations of motion in physics
  • Basic knowledge of energy conservation principles
  • Ability to manipulate algebraic equations
NEXT STEPS
  • Calculate the height of the first bounce using the derived equation
  • Explore the effects of different energy loss percentages on bounce height
  • Investigate the role of air resistance in energy loss during free fall
  • Learn about the relationship between mass, energy, and height in physics
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and energy conservation, as well as educators looking for practical examples of energy loss in real-world scenarios.

aleferesco
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Homework Statement



A basketball is dropped from a height of 2m. It lost lost 20% of its energy, in the bouncing from the floor due to friction in the air, before it reaches the highest point of its first bouncing. How high did it bounce?

h1= 2m
h2=?
g=9.8m/s^2

Homework Equations



PE = mgh and Energy Total (initial)=Energy Total (final)

mgh1 = 0.20 + mgh2

The Attempt at a Solution



I don't know how to solve it without the mass and kinetic energy
 
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aleferesco said:

Homework Statement



A basketball is dropped from a height of 2m. It lost lost 20% of its energy, in the bouncing from the floor due to friction in the air, before it reaches the highest point of its first bouncing. How high did it bounce?

h1= 2m
h2=?
g=9.8m/s^2

Homework Equations



PE = mgh and Energy Total (initial)=Energy Total (final)

mgh1 = 0.20(?)[/color] + mgh2
check this equation for an error...20% of what?

The Attempt at a Solution



I don't know how to solve it without the mass and kinetic energy
What's the initial KE at the release point? What's the final KE at the top of the first bounce?
 

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