How much energy is dissipated in the first bounce?

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Homework Help Overview

The problem involves a basketball dropped from a height of 1.4 m that rises to 66% of its original height after the first bounce. The focus is on calculating the energy dissipated during this bounce.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the initial potential energy of the basketball and question how to determine the total energy at the start and after the first bounce. There are inquiries about the need for kinetic energy and the implications of the ball being dropped with zero initial speed.

Discussion Status

The discussion is ongoing, with participants exploring the relationship between potential and kinetic energy. Some guidance has been provided regarding the potential energy after the first bounce, but there is no explicit consensus on the method to calculate the energy dissipated.

Contextual Notes

Participants express uncertainty about the need for additional information, such as speed, and the implications of the problem's wording regarding the initial conditions of the basketball's drop.

emily081715
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Homework Statement


A 0.70-kg basketball dropped on a hardwood floor rises back up to 66 % of its original height. If the basketball is dropped from a height of 1.4 m , how much energy is dissipated in the first bounce?

Homework Equations


U=mgy

The Attempt at a Solution


U=(0.70)(9.8)(1.4)
=9.604 J
i'm not sure where the error is
 
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That's the potential energy that the basketball started with. How much total energy did the basketball start with?

Now, can you tell how much energy the basketball had after the first bounce?
 
olivermsun said:
That's the potential energy that the basketball started with. How much total energy did the basketball start with?

Now, can you tell how much energy the basketball had after the first bounce?
how do i find how much energy it starts with, i thought that would be the potential energy? would i need to find energy by adding potential and kinetic, cause if so, i don't have a speed
 
Typically in these problems if they say the ball was "dropped" they mean it was just released with 0 initial speed.

So what about the info you are given regarding the energy after the first bounce?
 
olivermsun said:
Typically in these problems if they say the ball was "dropped" they mean it was just released with 0 initial speed.

So what about the info you are given regarding the energy after the first bounce?
wouldn't i still need the final energy to calculate the kinetic energy of the first bounce? after the bounce is 66% of the original height so 0.924m
 
You have the max height after the first bounce, so that tells you the potential energy. What is the kinetic energy at the very moment that the max height is achieved?
 
olivermsun said:
You have the max height after the first bounce, so that tells you the potential energy. What is the kinetic energy at the very moment that the max height is achieved?
0?
 
Sure, so you have all the information you need.
 
olivermsun said:
Sure, so you have all the information you need.
how?
 
  • #10
emily081715 said:
how?
do i just subtract potential energies from the start and the max of second bounce
 
  • #11
This part I leave to you to consider. :wink:
 
  • #12
emily081715 said:
do i just subtract potential energies from the start and the max of second bounce
the answer is 3.3 thanks for walking me through
 

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