How High Does a Coin Tossed Straight Up Reach?

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SUMMARY

The maximum height reached by a coin tossed straight up, taking 2.75 seconds to return to its initial release point of 1.30 meters, can be calculated using kinematic equations. The initial velocity (V0) is determined to be 13.475 m/s, derived from the formula V0 = g * (t/2), where g is the acceleration due to gravity (9.81 m/s²). The maximum height is then calculated using the equation H = initial height + (V0² / (2g)), resulting in a total maximum height of approximately 5.52 meters.

PREREQUISITES
  • Understanding of kinematic equations in physics
  • Knowledge of gravitational acceleration (9.81 m/s²)
  • Ability to manipulate algebraic equations
  • Familiarity with concepts of projectile motion
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  • Study kinematic equations in detail, focusing on projectile motion
  • Learn how to derive initial velocity from time of flight
  • Explore real-world applications of projectile motion in sports and engineering
  • Practice solving similar problems involving vertical motion and maximum height
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Homework Statement


A coin tossed straight up into the air takes
2.75 s to go up and down from its initial
release point 1.30 m above the ground.

What is its maximum height?


Homework Equations




The Attempt at a Solution





I seriously have no clue how to do this problem. I really need a detailed explanation with steps. I'm sorry if this doesn't abide by your question standards, but I really mean I have 0 idea how to solve this problem, and I really need some help.


Thanks.
 
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can anyone help?
 
its 1.30 + V0^2/2g

since V^2=V0^2 + 2g(ay) where the max height is when V=0
 
where V0=g(2.75/2) since V= V0 + gt where V=0m/s since you are accounting for the time it takes and the velocity at the point it goes its max height.
 

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