Medgirl314
- 568
- 2
s = Vt - 0.5 at2
1=0-0.5(-9.8)t^2
1=-0.5(-9.8)t^2
t=0.45 s
Thanks! Is that better?
1=0-0.5(-9.8)t^2
1=-0.5(-9.8)t^2
t=0.45 s
Thanks! Is that better?
The problem involves a basketball player leaping from a stationary position and reaching a height of 1.0 m. The main question is to determine how long the player is in the air during the jump.
Participants are actively engaging with the problem, exploring different equations and clarifying the relationships between variables. Some have suggested using specific SUVAT equations, while others are questioning the assumptions about initial and final velocities.
There is a recognition of the need for additional equations to find the initial velocity, and participants are considering the implications of the upward and downward motion in their calculations. The discussion includes a mix of correct and incorrect assumptions that are being examined.