How high does the basketball player leap?

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A basketball player leaps from a stationary position, reaching a height of 1.0 m. The discussion focuses on calculating the time the player is in the air using kinematic equations. The final velocity at the peak of the jump is zero, and the acceleration due to gravity is 9.8 m/s². The time to reach the peak is calculated to be approximately 0.45 seconds, which is the same for the descent, totaling about 0.90 seconds in the air. The conversation emphasizes the importance of using the correct equations and understanding initial velocity in the context of the jump.
  • #31
s = Vt - 0.5 at2
1=0-0.5(-9.8)t^2
1=-0.5(-9.8)t^2
t=0.45 s

Thanks! Is that better?
 
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  • #32
Looks good.
 
  • #33
Great, thanks again! So is this my final answer, or is that just the time it took for him to go *up*?
 
  • #34
Great, thanks again! So is this my final answer, or is that just the time it took for him to go *up*?
 
  • #35
Well spotted, I'd missed that. Yes just the time to go up. The time to come down will be the same.
 
  • #36
Great, thanks!
 

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