The discussion focuses on calculating the altitude of a spaceship that accelerates to 340 km/h in 1.1 minutes. The correct approach involves determining the acceleration, which is 1.43 m/s², and applying the kinematic equation xf = xi + vi*t + 1/2at². The final altitude at t = 66 seconds is calculated to be approximately 9347.58 m, which should be expressed as 9.3 x 10³ m for two significant figures. Misapplication of the equations led to initial incorrect calculations of 6233.04 m.
PREREQUISITESThis discussion is beneficial for physics students, educators, and anyone interested in understanding the principles of motion under constant acceleration.
You plugged in the final velocity, but was it traveling with that velocity the whole time? What was the average velocity, given the acceleration was constant?Manh said:
Manh said:
This equation doesn't describe the body in acceleration...Manh said:
a = 94.44/66 = 1.43 m/s^2DaniV said:
Thats right!Manh said:
I submit the answer but it is still incorrect according to Mastering PhysicsDaniV said:Thats right!
This is incorrect. The initial velocity is zero. Only the 3rd term should be in there. Alternately, the average speed is (94.44)/2 = 47.22 m/sec, so the distance should be half your original answer 6233/2 = 3117 m. Either way, you will get the same answer.Manh said: