How High is the Building and What is the Stone's Velocity Before Impact?

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Homework Help Overview

The problem involves a stone being dropped from the top of a building, with a focus on determining the height of the building and the stone's velocity just before impact. The context is rooted in kinematics, specifically the equations of motion under constant acceleration due to gravity.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the initial conditions of the problem, particularly questioning the assumption of initial velocity. Some express confusion regarding the teacher's provided solution, while others clarify that if the stone is dropped, the initial velocity should be zero.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the initial conditions and the implications for the calculations. There is acknowledgment of potential errors in the teacher's solution, but no consensus has been reached regarding the correct approach.

Contextual Notes

There is a noted ambiguity regarding the initial velocity, as the problem states the stone is dropped, which typically implies an initial velocity of zero. Participants are considering this assumption in their reasoning.

libido_07
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Homework Statement


A stone is dropped from the top of a building. If it takes 5 seconds for the stone to hit the ground, how high is the building? What is the velocity just before it hits?


Homework Equations


d=Vit + 1/2[g(t^2)]
Vf=Vi + gt

The Attempt at a Solution


=1m/s(5s) + 1/2[9.8m/s^2(5s^2)]
=122.5m downward
=0 + 9.8m/s^2(5s)
=49m/s downward
 
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Where did you get the initial velocity from?
 
that is the problem...cause that solution was given to us by our teacher...and I'm wondering how did she get it...
 
If the stone is dropped that assumes that the initial velocity is 0. If it was stated the stone was thrown with an initial velocity of 1m/s then the solution would make sense.

From what you have put though the answer is correct and the teacher hasn't included the initial velocity to get the height of the building in the calculation. Perhaps just an error on her part, teachers are humans too you know. :wink:
 
tnx...
-stacy libido
 

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