How High Is the Diving Platform?

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Homework Help Overview

The problem involves calculating the height of a diving platform based on a jump with a specified horizontal velocity and time of flight, while considering gravitational effects.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between vertical and horizontal motion, questioning the initial vertical velocity and the appropriate kinematic equations. There is uncertainty about how to handle multiple variables in the equations.

Discussion Status

Some participants have offered guidance on the correct kinematic equations to use, while others are exploring the implications of the initial conditions. Multiple interpretations of the problem are being examined, particularly regarding the initial vertical velocity and its impact on the calculations.

Contextual Notes

Participants note that the problem may involve assumptions about the initial vertical velocity and the direction of displacement in relation to gravity. There is also mention of the learning context, indicating that some concepts have not yet been covered in their studies.

Londoncalling
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Homework Statement



You jump off a diving board with a horizontal velocity of 1.81 and land in the water 1.4 seconds later. Gravity=9.8. How high is this platform?

Homework Equations


x=2.534, if that helps.


The Attempt at a Solution


I got 7.07 but this is not right...
 
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Hi Londoncalling, welcome to PF.
What is the velocity in the vertical direction? What is the kinematic equation, which relates the initial velocity, time , acceleration and displacement?
 
y=vit-.5gt2 right?
I'm not sure though, we haven't learned it yet.
 
In the vertical direction the initial velocity is ...?
Your equation is right. But put -y for the displacement because it is also in the downward direction like g.
 
Okay so -y=vi -.5*9.8*1.42.
Then -y=vi*1.4-(4.9*1.96)
-y=vi*1.4-(9.604)
But there are 2 variables and only one equation... I thought you couldn't do that...?
 
Or is your horizontal v of 1.81 the initial velocity?
 
The vertical velocity is zero.
 
So it's 9.604 m high then?
Edit: Yes, I got it right! Thank you SO much, you have no idea how relieved I am. Would you be able to help me with another problem (it's in a different post)...?
 

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