How high will a ball thrown with an initial speed of 80 ft/sec be at 3 seconds?

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SUMMARY

The height of a ball thrown upward with an initial speed of 80 ft/sec after 3 seconds is calculated using the formula h = Vo*t - 1/2 g*t². Substituting the values, where Vo is 80 ft/sec, g is 32 ft/sec², and t is 3 seconds, the height h is determined to be 96 ft. This calculation confirms that the initial attempt at the solution is correct.

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Homework Statement



a ball is thrown upward with an initial speed of 80 ft/sec.

Homework Equations



how high is it at 3 seconds...?

The Attempt at a Solution



using the formula:h = Vo*t - 1/2 g*t2
where h as the height
Vo is the original velocity
g as the gravitational pull : 32ft/sec
and t as the time...


my attempt answer is 96 ft...


is this correct?
 
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