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## Homework Statement

You are given a pendulum composed of a 0.015 kg mass on the end of a 0.40 m long massless string. If the pendulum is moved 30° from the vertical and given an initial speed of 0.45 m/s tangent to the support string and away from the vertical, how much higher relative to the release point of the pendulum swing will the pendulum rise?

## Homework Equations

(1/2)mv

^{2}+ mgh

_{1}= mgh

_{2}

h=L(1-cosθ)

## The Attempt at a Solution

I plugged in the values, using the second equation to find the initial height.

Mass cancels out and I have (1/2)(.45)

^{2}+ (9.8)(.4)(1-cos(30)) = (9.8)(h

_{2})

Solving this gives the resultant height of 0.063921 m. Subtract the release height of 0.052518 m, I get that it rises 0.01033≈0.010 meters higher, however this answer is incorrect.