How in the world is current passing through?

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Homework Help Overview

The problem involves calculating the magnetic field inside a toroidal coil used in a tokamak fusion reactor, with specific parameters regarding the coil's dimensions and current. The discussion centers around the behavior of magnetic fields in relation to Amperian loops and current enclosures.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between Amperian loops and the magnetic field, questioning how current can exist within the toroidal structure. They discuss the implications of drawing loops of various sizes in relation to the toroid.

Discussion Status

The discussion is ongoing, with participants providing insights into the behavior of magnetic fields and current enclosures. There is a focus on clarifying the conditions under which the magnetic field is present or absent based on the size of the Amperian loop.

Contextual Notes

Participants are navigating assumptions about current distribution and the validity of different Amperian loop configurations in relation to the toroidal coil.

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Homework Statement



The magnetic coils of a tokamak fusion reactor are in the shape of a toroid having an inner radius of 0.700 m and an outer radius of 1.30 m. The toroid has 900 turns of large-diameter wire, each of which carries a current of 14.0 kA.

(a) Find the magnitude of the magnetic field inside the toroid along the inner radius.
___T
(b) Find the magnitude of the magnetic field inside the toroid along the outer radius.
___T

The Attempt at a Solution



(a) I did it the way the textbook wants me to and I got 3.6T, but I don't understand, how could there be a current inside the torus? I mean if I were to enlarge my Amperian loop, I can get a current passing through

(b) Same here, if I were to draw an Amperian loop that is bigger than the torus, wouldn't it be zero? BUt the loop is still valid for it encloses the torus right?
 
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From Wikipedia:
400px-Toroidal_Inductor-Simple_with_Axes.JPG


Something like this.
 
Where is the Amperian loop in the picture?
 
Right...if you draw an amperian loop (a circle that is coaxial with the torus) that is smaller than the inner radius, you enclose no current, thus no B-field. If you draw it so the radius of the loop is between the inner and outer radii of the torus, you enclose N*I, and r*d(theta) (or your differential line element on the circumference of the amperian loop) is always parallel to the B-field (B (dot) dl = BL = B2*Pi*r. If you draw it larger than the outer radius, you enclose net 0 current, and have net 0 B-field.
 
A circle within the blue ring itself.
 

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