Undergrad How is a binomial expansion done?

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SUMMARY

The discussion focuses on the application of binomial expansion in the context of multipole expansion as presented in Griffiths' "Introduction to Electrodynamics" (4th Edition). The user seeks clarification on approximating the expression for š“‡^2_{\pm} in the regime where r >> d. The binomial expansion is utilized to simplify the expression, leading to the result that 1/š“‡^2_{+} - 1/š“‡^2_{-} ā‰ˆ (d/r^2)cosĪø. Key insights include the use of the generalized binomial expansion and its relation to Taylor series, which are essential for understanding approximations in physics.

PREREQUISITES
  • Understanding of binomial expansion and its generalized form.
  • Familiarity with Taylor series and their applications in physics.
  • Basic knowledge of multipole expansion in electromagnetism.
  • Proficiency in calculus, particularly in handling limits and approximations.
NEXT STEPS
  • Study the generalized binomial expansion formula and its applications.
  • Learn about Taylor series and their derivations, focusing on Taylor expansions of functions.
  • Explore the concept of multipole expansion in electromagnetism for practical applications.
  • Review calculus techniques for approximating functions and limits, particularly in physics contexts.
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Students preparing for exams in electromagnetism, particularly those studying multipole expansions, as well as anyone looking to strengthen their understanding of binomial and Taylor series in physics.

CrosisBH
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Can someone give me a basic high level overview on how to do a binomial expansion?
Summary: Can someone give me a basic high level overview on how to do a binomial expansion?

I'm studying for my E&M test and going over multipole expansion. I'm particularly confused about these lines (Griffiths E&M 4th Edition)

š“‡^2_{\pm} = r^2 \left(1\mp \frac{d}{r} \cos\theta + \frac{d^2}{4r^2}\right)

We're interested in the rƩgime r>>d, so the third term in negligible, and the binomial expansion yields

\frac{1}{š“‡^2_{\pm}} \cong \frac{1}{r} \left( 1 \mp \frac{d}{r}\cos\theta\right)^{-1/2}\cong \frac{1}{r}\left(1\pm\frac{d}{2r}\cos\theta\right)

Thus

\frac{1}{š“‡^2_{+}} - \frac{1}{š“‡^2_{-}} \cong \frac{d}{r^2}\cos\theta

I understand how the first line was derived, and I understand the first half on the second line, but I don't understand how the approximation was made in the second half. It's called a binomial expansion apparently, but all my research seems to point toward expanding an integer power binomial

(a+b)^2 = a^2 + 2ab + b^2

And anything about a generalized form is written with binomial coefficients which I can't seem to wrap my head around, and right now it seems beyond my math level to understand it formally. Could someone give me a physics level rigor on how this expansion is done? This'll probably be on my next exam and I want to understand it.
 
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The general binomial expansion is:

##(1 + x)^n = 1 + nx + \frac {n(n - 1)} { 2! } x^2 + ...##

It's still valid if n = -1/2

and so in your case ## x = \frac d { 2r } cos \theta##

and so you get ##\frac 1 {r_{-}^2} = \frac 1 r (1 - \frac d { 2r } cos \theta) ##

and ##\frac 1 {r_{+}^2} =\frac 1 r (1 + \frac d { 2r } cos \theta)##

and hence you get

## \frac 1 {r_{+}^2} - \frac 1 {r_{-}^2} = \frac 1 r (1 + \frac d { 2r } cos \theta) - \frac 1 r (1 - \frac d { 2r } cos \theta) = \frac d { r^2 } cos \theta##

Does that make sense ?

https://socratic.org/questions/how-do-you-use-the-binomial-series-to-expand-1-x-1-2
 
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Likes CrosisBH and Mark44
It is also a special case of the Taylor expansion, expand ##(1+x)^c## around x=0.
 
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Likes jedishrfu
That makes perfect sense. After I posted this, I consulted my current Math Professor (Diff eq and Linear Algebra) and he explained it was an infinite series but he forgot the exact equation but I should be able to find it. Then I come here and jedishrfu posted the equation I needed and went through the math, and mfb explained it was derived from the Taylor Series. I honestly haven't touched a Taylor Series since Calc 2 a year ago and I forgot they were a thing. My professor would probably give a very similar problem to this one and I should just memorize.
(1+x)^{-1/2} \cong 1-\frac{1}{2}x

I've heard that Taylor Series expansions are so common in physics so I should just start getting used to them. Thank you everyone!
 
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Likes WWGD
Relativistic Momentum, Mass, and Energy Momentum and mass (...), the classic equations for conserving momentum and energy are not adequate for the analysis of high-speed collisions. (...) The momentum of a particle moving with velocity ##v## is given by $$p=\cfrac{mv}{\sqrt{1-(v^2/c^2)}}\qquad{R-10}$$ ENERGY In relativistic mechanics, as in classic mechanics, the net force on a particle is equal to the time rate of change of the momentum of the particle. Considering one-dimensional...

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