How Is Acceleration Calculated in a Pinball Machine?

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Homework Help Overview

The discussion revolves around calculating the acceleration of a pinball in a machine, where the ball accelerates from rest to a final speed of 11 in/s over a distance of 4 inches. Participants are exploring the application of kinematic equations to determine the acceleration.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to use kinematic equations, specifically Vf = Vo + at and Vf^2 = Vo^2 + 2a∆x, to find acceleration. Some express confusion over calculating time correctly, noting that the ball does not travel at a constant speed. Others suggest calculating average speed or using different kinematic equations.

Discussion Status

There is an ongoing exploration of the problem, with participants sharing their reasoning and questioning their calculations. Some guidance has been offered regarding the correct interpretation of the motion involved, but no consensus has been reached on the method to solve for acceleration.

Contextual Notes

Participants are working under the assumption that the initial velocity is zero and are trying to reconcile their calculations with the kinematic equations. There is a noted difficulty in determining the time variable correctly due to the nature of the acceleration involved.

smashbrohamme
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The ball of a pinball machine is accelerated from rest to 11in/s in a distance of 4in. Determine the acceleration of the ball


V=Vo +at
A= Change of Velocity/ Change of Time

The answer is 15.1 in/s^2



The time the pinball traveled was 4inches/11in - .36sec
I can't seem to get what I am doing wrong but I am not getting 15.1in/s^2
I am doing 11in/s= 0+a(.36) A= 30.5
I also tried doing change of velocity/change of time which is just 11/.36 as well.

Since Vo= 0 The change of velocity is simply 11/in/s^2 and the change of time is simply
.36seconds
 
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smashbrohamme said:
The ball of a pinball machine is accelerated from rest to 11in/s in a distance of 4in. Determine the acceleration of the ball


V=Vo +at
A= Change of Velocity/ Change of Time

The answer is 15.1 in/s^2



The time the pinball traveled was 4inches/11in - .36sec
I can't seem to get what I am doing wrong but I am not getting 15.1in/s^2
I am doing 11in/s= 0+a(.36) A= 30.5
I also tried doing change of velocity/change of time which is just 11/.36 as well.

Since Vo= 0 The change of velocity is simply 11/in/s^2 and the change of time is simply
.36seconds
You are not calculating the time correctly. The ball is not traveling at a constant speed of 11 in/sec...its speed varies from 0 to 11 in/sec.. You can calculate its average speed to find the time, or use one of the other kinematic equations.
 
This is how I was taught. Write out everything you know first. (Dont skip steps)
Vo, initial velocity
Vf, final velocity
∆x, delta x, or displacement x

We need to find
a, acceleration

Now we take a look at the four of our kinematics,
U1L6a1.gif
In order to solve for a variable in an equation we must have all the variables but one.

We have all the variables for this equation
Vf^2=Vo^2+2a∆x

Except acceleration, but that's what were solving for : )

P.S. Our initial velocity is 0 So we can simplify this equation
Vf^2=2a∆x
 
Last edited:
Lavid2002 said:
This is how I was taught. Write out everything you know first. (Dont skip steps)
Vo, initial velocity
Vf, final velocity
∆x, delta x, or displacement x

We need to find
a, acceleration

P.S. Our initial velocity is 0 So we can simplify this equation
Vf^2=2a∆x
Correct! Solve for a.
 

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