How Is Displacement Derived from Velocity-Time Graphs?

[Alipepsi]

Derive for time!
D=Vit+1/2at^2

THANKS for you help

 

[Dickfore]

The displacement is given by the area under the velocity-time graph. Your velocity-time equation is:
<br /> v(t) = v_i + a t<br />
and between the vertical lines t_1 = 0 and t_2 = t. The geometric figure is a right trapezoid (trapzium outside U.S.) and the area is:
<br /> D = \frac{1}{2} \left[ v_i + (v_i + a \, t) \right] \cdot t = v_i \, t + \frac{a \, t^2}{2}<br />