How is energy conserved in General Relativity?

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SUMMARY

The discussion centers on the conservation of energy in General Relativity (GR), specifically addressing the implications of the Schwarzschild metric and the covariant divergence of the stress-energy tensor. Participants clarify that while classical conservation laws apply in flat spacetime, in GR, energy conservation is more complex and can only be approximated due to the influence of gravitational fields. The relevant conservation relation in GR is expressed as T^{\mu\nu}_{:\nu}=0, contrasting with the classical form T^{\mu\nu}_{,\nu}=0, which does not hold in curved spacetime. The concept of "energy at infinity" is introduced as a conserved quantity in stationary spacetimes, providing a framework for understanding gravitational potential energy.

PREREQUISITES
  • Understanding of General Relativity (GR) principles
  • Familiarity with the Schwarzschild metric
  • Knowledge of the stress-energy tensor and its divergence
  • Basic concepts of covariant derivatives in curved spacetime
NEXT STEPS
  • Study the implications of the Schwarzschild metric on energy conservation in GR
  • Learn about the concept of "energy at infinity" in stationary spacetimes
  • Explore the covariant divergence of the stress-energy tensor in GR
  • Investigate the role of gravitational redshift in energy calculations
USEFUL FOR

Physicists, students of General Relativity, and anyone interested in the complexities of energy conservation in curved spacetime.

  • #61
sweet springs said:
is wrong?

It's ok as far as it goes. The errors in your previous posts came after that equation.

sweet springs said:
Normality of 4-velosity

The 4-velocity is a unit vector in GR, yes.
 
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  • #62
sweet springs said:
tells us about speed, doesn't it ?

It's true that ##u^1## tells you something about speed; but it's not equal to speed. (Also, you need to be careful how you're defining "speed". Speed relative to what?)
 
  • #63
sweet springs said:
Why this top position in trajectory was chosen to give the value ?
Because at the top v=0 so it is easier to calculate. Remember, the energy is a constant over the whole trajectory, so we can pick any point to calculate it. We may as well pick a point that makes the math easier
 
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  • #64
stevendaryl said:
Second, using the effective Lagrangian above, we could form the corresponding Hamiltonian, which is a conserved quantity. However, as I said, as a conserved quantity, it's kind of boring, since its value is just 12mc2\frac{1}{2} mc^2. So it's independent of the motion of the test particle.
It's independent of the motion and the position. Even ##\gamma## at infinity is disregarded. It is equal to rest mass in local Minkowsky space where the body is at rest. I am afraid that might be all that GR says about energy rigorously.
 
  • #65
sweet springs said:
I am afraid that might be all that GR says about energy rigorously.

No, it isn't. An object's energy at infinity is not in general the same as its rest mass. That is obvious from the equation for energy at infinity that we have already derived.

Also, as I have already pointed out, the term "energy" has multiple meanings. Several of them have been covered in this thread, and energy at infinity is only one of them.

At this point I am closing the thread. I think you need to consider more specifically what concept of energy you want to ask about, so that future threads can have a more focused and useful discussion.
 

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