How Is Impulse Calculated in a Two-Dimensional Collision?

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SUMMARY

The impulse associated with a two-dimensional collision can be calculated using the formula F dt = m*v. In this scenario, a ball with a mass of 7.0 g and a speed of 25.2 m/s strikes a wall at an angle of 23.0° and rebounds with the same speed and angle. The contact time with the wall is 39.0 ms. To determine the magnitude of the impulse, it is essential to resolve the velocity into components using trigonometric functions, focusing on the axis perpendicular to the wall.

PREREQUISITES
  • Understanding of impulse and momentum concepts
  • Knowledge of trigonometric functions for vector resolution
  • Familiarity with basic physics equations, specifically F dt = m*v
  • Ability to visualize two-dimensional motion and collisions
NEXT STEPS
  • Study vector resolution techniques in two-dimensional physics problems
  • Learn about impulse-momentum theorem applications in collisions
  • Explore examples of two-dimensional collision problems in physics textbooks
  • Investigate the effects of angle on impulse and force calculations
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Physics students, educators, and anyone interested in understanding the dynamics of collisions and impulse calculations in two-dimensional motion.

chaotixmonjuish
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A ball of mass 7.0 g with a speed of 25.2 m/s strikes a wall at an angle 23.0 ° and then rebounds with the same speed and angle. It is in contact with the wall for 39.0 ms. What is the magnitude of the impulse associated with the collision force?
What is the average force exerted by the ball on the wall?

The only equation I know for impulse is:
F dt=m*v

I'm not sure how to treat this problem since it has an angle, and impulse isnew.
 
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try drawin a picture : then set some coordinates and then use trigonometric functions to see what's the speed in the axis that's in the right angle towards your wall (sounds confusing?) and then just apply it to the equation you have
 

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