How Is Laser Beam Intensity Calculated?

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SUMMARY

The intensity of a focused helium-neon laser beam with a power of 3.50 mW and a wavelength of 633 nm is calculated using the formula I = P / A, where A is the area of the focused spot. The effective diameter of the spot is given as 2.00 wavelengths, which translates to a radius of 633 nm. The correct approach involves calculating the area of the circular spot rather than using the spherical intensity formula, leading to a more accurate determination of the beam's intensity.

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  • Understanding of laser physics and beam properties
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  • Knowledge of circular area calculations
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Homework Statement


A helium-neon laser of the type often found in physics laboratories has a beam power of 3.50 mW at a wavelength of 633 nm. The beam is focused by a lens to a circular spot whose effective diameter may be taken to be equal to 2.00 wavelengths. Calculate the intensity of the focused beam.

Homework Equations


<br /> <br /> I = P / 4\pi r^2<br /> <br />

The Attempt at a Solution


<br /> <br /> I = P / 4\pi r^2<br /> <br />

P = 3.50mW
I don't know what the radius is. From the problem, I used 633nm as the radius because the diameter = 2*(633nm), I used 633nm as the radius, but after using that value the answer is wrong. If someone can tell me the radius, I think I could get this problem. Thanks
 
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Hi ganondorf29! :smile:

(have a pi: π :wink:)
ganondorf29 said:
A helium-neon laser of the type often found in physics laboratories has a beam power of 3.50 mW at a wavelength of 633 nm. The beam is focused by a lens to a circular spot whose effective diameter may be taken to be equal to 2.00 wavelengths. Calculate the intensity of the focused beam.

I = P / 4\pi r^2

No, that's the wrong formula …

as you can see, it's the total power divided by the surface area of a whole sphere of radius r …

it applies when the beam is all-round, so the intensity is P/4πr2 , and the power through an area A (at distance r) is PA/4πr2.

In this case, the total power is confined to the beam, and it all goes through the "effective circle", so the appropriate formula for intensity is … ? :smile:
 

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