How Is Minimum Sensitivity Calculated in Instruments?

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SUMMARY

The minimum sensitivity of an instrument or transducer is calculated as the derivative of the output voltage with respect to the measured quantity, specifically distance in this case. By substituting the maximum input value of 5.0 mm into the equation E = 9.5e-0.4(5.0), the output voltage is determined to be 1.286 V, which represents the minimum voltage rather than sensitivity. The correct approach involves calculating the derivative, yielding a sensitivity of -0.514 V/mm, which should be expressed as an absolute value of 0.514 V/mm, as negative sensitivity is not meaningful in this context.

PREREQUISITES
  • Understanding of sensitivity in measurement instruments
  • Knowledge of calculus, specifically derivatives
  • Familiarity with voltage-output relationships in transducers
  • Basic concepts of displacement measurement
NEXT STEPS
  • Study the principles of sensitivity in measurement systems
  • Learn how to calculate derivatives in practical applications
  • Explore the relationship between voltage and distance in transducer outputs
  • Investigate the significance of absolute values in sensitivity calculations
USEFUL FOR

Students in engineering or physics, instrument designers, and anyone involved in the calibration and analysis of measurement devices will benefit from this discussion.

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Homework Statement
11kd1r5.jpg


The attempt at a solution
First, we define sensitivity as the change of an instrument or transducer's output per unit change in the measured quantity.

So to find the minimum sensitivity I simply plugged in the largest possible input (5.0 mm) into the equation:

E = 9.5e-0.4(5.0)

E = 1.286 V

Is this correct?
 
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I would say no, that is in fact the "minimum voltage" you would expect to occur

I would associate sensitivity with rate of change of voltage with distance
 


So I would first have to take the derivative, and then plug in 5.0?

Doing this I would get an answer of -0.514 V/mm. So will my final answer be 0.514 V/mm, if I were to take the absolute value?
 
Last edited:


if you can explain why you choose 5 (which is a reasonable choice), it sounds like a plan
 


I chose a displacement of 5.0 mm because it will give me the smallest rate of change, whereas if I chose a number closer to 0, I would get a higher rate of change, which means higher sensitivity.

Also, do I keep the value negative, or take the absolute value? I don't think negative sensitivity makes sense.
 


may have to check you notes, it may be defined as the magnitude of rate of change as you're hinting
 

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