Calculate the minimum uncertainty

Click For Summary

Homework Help Overview

The discussion revolves around calculating the minimum uncertainty in the vertical component of momentum for photons passing through a narrow slit, as well as estimating the width of the central diffraction maximum on a screen. The problem is situated within the context of wave-particle duality and uncertainty principles in physics.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the equation for minimum uncertainty and its derivation, questioning the relevance of certain parameters like the distance to the screen. There is an exploration of the dimensions of the uncertainty in momentum and its implications.

Discussion Status

Some participants have provided guidance on the equations involved and the context of the problem. There is acknowledgment of differing interpretations regarding the relevance of specific variables, and one participant indicates they have resolved their issue.

Contextual Notes

Participants reference a specific textbook for the equations and context, indicating that the problem is part of a broader discussion on wave-particle duality and uncertainty. There is mention of potential confusion regarding the dimensions of the quantities involved.

Kaspar
Messages
3
Reaction score
1
Hello,
can anybody help me with solving the problem.

Homework Statement

:[/B]
Calculate minimum uncertainty?

A horizontal beam of laser light of wavelength 604 nm passes through a narrow slit that has width 0.0600 mm . The intensity of the light is measured on a vertical screen that is 2.40 m from the slit.

a.) What is the minimum uncertainty in the vertical component of the momentum of each photon in the beam after the photon has passed through the slit?
∆p_y=?

b.)Use the result of part A to estimate the width of the central diffraction maximum that is observed on the screen.
d=?

Homework Equations

and

The Attempt at a Solution

:
[/B][/B]

a.) I tried using this equation and I got for ∆p_y=0.02416m
But it was wrong. :frown:

See in picture.

Can anybody help me?
Thank you.
M
pic.png

pic2.png

 

Attachments

  • pic2.png
    pic2.png
    4.4 KB · Views: 3,331
  • pic.png
    pic.png
    1.7 KB · Views: 3,080
Physics news on Phys.org
Hello Kaspar, :welcome:

Kaspar said:
I tried using this equation
I suppose you tried ##\Delta p_y = p_x{\lambda\over a}## ? Where does that come from ? And for ##p_x## you use the distance to the screen ?

I got for ∆p_y=0.02416 m
A ##\Delta p## with the dimension of m ?

In what context is this exercise ? Does the textbook mention uncertainty somewhere ?
 
BvU said:
Hello Kaspar,
I suppose you tried ##\Delta p_y = p_x{\lambda\over a}## ? Where does that come from ? And for ##p_x## you use the distance to the screen ?

Hi BvU, thanks for your reply. The equation comes from the textbook "University of Physics - Modern physics" by Zemansky (https://drive.google.com/drive/folders/13rAnc_ryXgKa3YQOXms2AGnbpFvqeXXd , book page 1268)

A ##\Delta p## with the dimension of m ?
In what context is this exercise? Does the textbook mention uncertainty somewhere ?

Yes its the chapter "38.4 WAVE–PARTICLE DUALITY, PROBABILITY, AND UNCERTAINTY"
But I still don't know how to calculate: ##\Delta p_y##
Dimension should be kg*m/s .
 
Kaspar said:
The equation comes from the textbook "University of Physics - Modern physics" by Zemansky
Ok, but the story continues on the next page !
 
BvU said:
And for pxpxp_x you use the distance to the screen ?
The distance to the screen cannot be relevant for part a). Isn't it just a matter of ΔyΔpy≥ etc?
 
haruspex said:
The distance to the screen cannot be relevant for part a). Isn't it just a matter of ΔyΔpy≥ etc?

You are right.

I solved my problem. Here you can see. Thank you.
solved.png
 

Attachments

  • solved.png
    solved.png
    14.5 KB · Views: 2,825
  • Informative
Likes   Reactions: skycutter

Similar threads

  • · Replies 10 ·
Replies
10
Views
9K
Replies
1
Views
2K
  • · Replies 16 ·
Replies
16
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 8 ·
Replies
8
Views
6K
  • · Replies 57 ·
2
Replies
57
Views
6K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
6
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K